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quadratic equations help

hey i need help with this word problem ive tried it but cant figure it out:

Kylie bought an item for $x and sold it for $10.56. If Kylie incurred a loss of x per cent, find x.
Sep 5 '07 #1
2 2057
Stwange
126 Expert 100+
hey i need help with this word problem ive tried it but cant figure it out:

Kylie bought an item for $x and sold it for $10.56. If Kylie incurred a loss of x per cent, find x.
Kylie bought it for $12, selling it for $10.56 and incurring a 12% loss,
or Kylie bought it for $88, selling it for $10.56 and incurring an 88% loss.

To work it out, x(1-(x/100)) = 10.56, multiply up to 100x(1-(x/100))=1056 and expand: x^2 - 100x + 1056 = 0, two answers are $88 and $12. Hope this helps.
Sep 5 '07 #2
r035198x
13,262 8TB
Moved to Maths and puzzles forum
Sep 5 '07 #3

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