hi everyone!here's the problem:
1729 2492 2411
what is the number that follows?????
16  2464 
i'll give you a hint...
one of the digits in the 4-digit number that follows is 8...
good luck!!
i'll give you a hint...
one of the digits in the 4-digit number that follows is 8...
good luck!!
Cool, down to 999 different options instead of 9999!
=P
Cool, down to 999 different options instead of 9999!
=P
Can you explain, What you mean?
Can you explain, What you mean?
Well its more than that, I just didnt want to take the time to figure it out. But if he takes the possible number we have to figure out down to three digits instead of four, it drastically drops the number of possibilities
Can you explain, What you mean?
We know that one of the digits is 8, so the possibilities have decreased from 9999 to 999. However, I don't think that's quite true. I can't be bothered explaining why - I'll leave that to someone else.
We know that one of the digits is 8, so the possibilities have decreased from 9999 to 999. However, I don't think that's quite true. I can't be bothered explaining why - I'll leave that to someone else.
It isnt quite true, because we dont know where the 8 is. So you could have:
8xxx
x8xx
xx8x
xxx8
So the possiblities are(?) 999 * 4 = 3996
1729 2492 2411
011011000001
100110111100
100101101011
6c1
9bc
96b
Just turning the number to binary and hex to see if anyone (or myself) can make something of it
I believe the answer is 1558
EDIT: How I got there:
011011000001 = 1729
100110111100 = 2492
100101101011 = 2411
011000010110 = 1558
If you notice, the patterns of the binary representations of these numbers go either:
11001100...
or
10101010...
So I just completed the pattern
It isnt quite true, because we dont know where the 8 is. So you could have:
8xxx
x8xx
xx8x
xxx8
So the possiblities are(?) 999 * 4 = 3996
That's still wrong :-(
If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.
However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
That's still wrong :-(
If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.
However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
Somehow I knew I was way off, lol
Considering the only two posts this member made were to post the question and the hint, I wonder if we will ever know the answer
Considering the only two posts this member made were to post the question and the hint, I wonder if we will ever know the answer
I know the first number is the Ramanujan - Hardy cab number (*) but I'm also
stuck in finding any regularity for the next numbers,
kind regards,
(*) the smallest non-trivial positive number that equals the sum of two cubes in
two different ways (1^3+12^3 == 9^3+10^3)
i attempted to delete this post...but couldn't figure out how.
That's still wrong :-(
If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.
However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
well this is not correct as well
since it is a 4 digit no.
8xxx
x8xx
xx8x
xxx8
u cant have the digit at thousandth position as 0
Now no. of possibility gets reduced to
8xxx = 10*10*10
x8xx = 9*10*10 since digit at thousandth position cant be 0
xx8x = 9*10*10
xxx8 = 9*10*10
so the no of possibilities are 3700
i attempted to delete this post...but couldn't figure out how.
There you are!!! That’s why this site allow admin to do that.
this one bugged me, so I went to google and searched for those three numbers, and the only thing that came up was rita's posts on 2 other forum sites, asking the same question. So, I fear that she was just some lurker who was hoping we'd do her homework FOR her.
:|
Although on one of the sites, someone guessed "2498" but didn't provide any reasoning on to how he came up with that number...
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