Trouble with excelp() (I'm very new to this)

[jazon]

I'm using C and attempting to pass something like this:

ret = execlp( "somefile", "somefile", num1, num2, (char *)0 );

Of course, that doesn't work.

This, on the other hand, works fine:

ret = execlp( "somefile", "somefile", argv[1], argv[2], (char *)0 );

That'd be great, but I can't just pass argv to it. Before it gets there I have to convert them to ints, do a little work on them, then pass them. How do I do this?? If I convert them back to char they don't pass correctly.

Say, somefile simply says

cout << argv[1] << endl;

If I'm lucky it'll print some random number, that I'm assuming is what's in some random address space.

Any help is greatly appreciated!!

[ashitpro]

I'm using C and attempting to pass something like this:

ret = execlp( "somefile", "somefile", num1, num2, (char *)0 );

Of course, that doesn't work.

This, on the other hand, works fine:

ret = execlp( "somefile", "somefile", argv[1], argv[2], (char *)0 );

That'd be great, but I can't just pass argv to it. Before it gets there I have to convert them to ints, do a little work on them, then pass them. How do I do this?? If I convert them back to char they don't pass correctly.

Say, somefile simply says

cout << argv[1] << endl;

If I'm lucky it'll print some random number, that I'm assuming is what's in some random address space.

Any help is greatly appreciated!!

Convert num1 and num2 to char * i.e. make them into string

[jazon]

Convert num1 and num2 to char * i.e. make them into string

Thanks a bunch! Works perfectly with sprintf!