second select of dynamic box

hello friends i hava a code like this and could any body help me with editing code and send me code. i am getting city values but i can't location values of city from database.thanks in advance. <html>

Expand|Select|Wrap|Line Numbers

 <head>

<title>demo</title>

<body>

<form method="POST" action="http://localhost/vtigercrm/modules/Webforms/

post.php">

 <input type="hidden" value="Leads" name="moduleName" />

 <table>

  <tbody>

   <tr>

      <td><label>Last Name</label></td>

      <td><input type="text" name="lastname" value="" /></td>

   </tr>

   <tr>

      <td><label>First Name</label></td>

      <td><input type="text" name="firstname" value="" /></td>

   </tr>

   <tr>

      <td><label>Company</label></td>

      <td><input type="text" name="company" value="" /></td>

   </tr>

   <tr>

      <td><label>email</label></td>

      <td><input type="text" name="email" value="" /></td>

   </tr>

   <tr><td><label>city</label></td><td colspan=1>

       <select name="city">

        <option>city</option>

<?php

$connect=mysql_connect("localhost","root","venkataz");

if(!$connect) die("access failed");

$select=mysql_select_db("vtigercrm530");

if(!$select) die("select failed");

echo "selected vtigercrm530";

$query="SELECT DISTINCT address_city FROM vtiger_users";

$result=mysql_query($query);

if(!$result) die("database access failed:" . mysql_error());

while($row = mysql_fetch_array($result))

{

  echo "<option value>".$row['address_city']."</option>";

}

?>

</select>

</tr>

<tr><td><label>lane</label></td><td colspan=1>

<select id="lane" onselect="show();">

<option>location</option>

<script type="text/javascript">

function show()

{

var lane=document.getElementById["lane"].selectedIndex;

alert(lane);

}

</script>

<?php

$connect1=mysql_connect("localhost","root","venkataz");

if(!$connect1) die("access failed");

$select1=mysql_select_db("vtigercrm530");

if(!$select1) die("select failed");

echo "";

echo "<br/>";

$query1="SELECT address_city FROM vtiger_users";

$result1=mysql_query($query1);

if(!$result1) die("database access failed:" . mysql_error());

$lcity=$_REQUEST["city"];

$rows=mysql_num_rows($result1);

for($j=0;$j<$rows;$j++)

if(mysql_result($result1,$j,"address_city")==$lcity)

{

 $query2="SELECT address_street FROM vtiger_users WHERE address_city='".mysql_result($result1,$j,'address_city')."'";

$result2=mysql_query($query2);

while($row= mysql_fetch_array($result2))

 {

echo "<option value>".$row['address_street']."</option>";

 }

}

?>

</select>

</td></tr>

  </tbody>

 <table>

 <input type="submit" value="Submit" />

</form>

</body>

</head>

</html>

Apr 20 '12 #1

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Stewart Ross

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Apr 21 '12 #2

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