JavaScript Style.display not working

I cant get the style.display property to work properly. I have this test html page:

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 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

    <title>Test Javascript</title>
 
    <script language="javascript" type="text/javascript">

        window.onload = function () {

            document.getElementById("button").onclick = function () {

                var text = document.getElementByName("username");

                var loader = document.getElementById("ajax_laoder");

                if (loader.style.display == "none") {

                    text.style.display = "none";

                    loader.style.display = "inline";

                } else {

                    text.style.display = "inline";

                    loader.style.display = "none";

                }

            }

        }

    </script>
 
</head>
 
<body>
 
<input type="text" name="username" value="Username" class="loginfield" maxlength="60" /><br />

<img src="images/ajax-loader.gif" alt="AJAX Loading" id="ajax_loader" style="display:none" /><br />

<input type="submit" id="button" value="replace" title="Replace" />

Basically, this has a textbox and a hidden gif, and a button called replace. When I click replace, the javascript doesnt do anything.

Oct 2 '10 #1

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✓ answered by drhowarddrfine

I believe it's getElementsByName with an 's' which means it will return an array and not just text.

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drhowarddrfine

7,435

Expert 4TB

I believe it's getElementsByName with an 's' which means it will return an array and not just text.

Oct 2 '10 #2

dgourd

Wow. I completely looked that one over. Thanks a lot dude.

Oct 2 '10 #3

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JavaScript Style.display not working

✓ answered by drhowarddrfine

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