How to find the value of a radio button

[donpro]

Hi,

Does anyone know how to use DOM to find the value of a selected radio
both (or if none were selected)?

My web page displays a set of radio buttons - the number is dynamic so
could be one or 100; I do this within a loop.

At the moment, I'm giving each one the same name and ID - not sure if
giving the same ID is correct or not. By default, no radio buttons
are selected when the page loads

When the user clicks on a a specific button on the page, I need to
check if a radio button was selected or not. I trap the 'click' event
but my code to get the radio button value has failed.

Thanks,
Don

[Peter Michaux]

On Jul 21, 5:41 pm, donpro <[e-mail]:

Hi,

Does anyone know how to use DOM to find the value of a selected radio
both (or if none were selected)?

My web page displays a set of radio buttons - the number is dynamic so
could be one or 100; I do this within a loop.

At the moment, I'm giving each one the same name and ID - not sure if
giving the same ID is correct or not. By default, no radio buttons
are selected when the page loads

When the user clicks on a a specific button on the page, I need to
check if a radio button was selected or not. I trap the 'click' event
but my code to get the radio button value has failed.

A good place to start is the group FAQ

http://jibbering.com/faq/#FAQ4_13

The longer FAQ note linked in the answer to the above FAQ is valuable.

Peter

[RobG]

On Jul 22, 10:41*am, donpro <[e-mail]:

Hi,

Does anyone know how to use DOM to find the value of a selected radio
both (or if none were selected)?

Yes, see Peter's reply.

My web page displays a set of radio buttons - the number is dynamic so
could be one or 100; I do this within a loop.

At the moment, I'm giving each one the same name and ID - not sure if
giving the same ID is correct or not.

It is not correct, the value of each ID attribute must be unique in
the page. Giving buttons the same name is OK, it forms them into
groups. Onlly give them IDs if they really need them.
--
Rob