Drop down menu failed to validate

[vinceboy]

Hi..guys.I have a static display drop down menu,however it doesn't go through the validation function when option is not selected.Thanks for your generious help...

<script language="JavaScript" type="text/JavaScript">
function formSubmit(ticket)
{
    var returnStatus = 1;
 
    if (ticket.rNumber.selectedIndex == 0) { 
        alert("Please select number of ticket!");
        returnStatus = 0;
    };
 
    if (returnStatus) { 
        window.location='home.php'
    }
}
</script>
 

<select name="rNumber" id="select4">
                      <option selected>Select</option>
                      <option>01</option>
                      <option>02</option>
                      <option>03</option>
                      <option>04</option>
                      <option>05</option>
                      <option>06</option>
</select>
 

<form action="" method="post" 
name="movieList" id="movieList">
.......
.......
.......
<input name="request" type="submit" id="request" value="Submit Request"    onclick="formSubmit(document.movieList)">
 

[acoder]

Use return false after the alert on line 8.

Instead of 0 and 1, consider using a boolean (true/false).

If you just change the location, the form value will not be sent to the next page. Set an action and let the form submit.

[vinceboy]

Actually the <form>tag was placed wrongly.However,when mixed with another dynamic radio button written in PHP,the validation of radio button become failed.

<script language="JavaScript" type="text/JavaScript">
function formSubmit(ticket)
{
    var returnStatus = 1;
 
    if (ticket.rNumber.selectedIndex == 0){ 
        alert("Please select number of ticket!");
        returnStatus = 0;
    };
   //if( !(movieList.time[php echo $rows['name'];?>].checked)){
          //alert("Please choose screening time!");
          //returnStatus = 0;
     //};   
    if (returnStatus) { 
        window.location='home.php';
    };
}
</script>
 
 

[PHP]

<?
if (isset($_SESSION['gmemberid'])) {

$tbl_name = "movie";
$result = mysql_query(sprintf('SELECT name,classification,screeningTime FROM %s
LIMIT 7', $tbl_name)) or die('Cannot execute query.');


//$numrow = mysql_num_rows($result);


while ($rows = mysql_fetch_assoc($result)) {
echo '<table width="100%" border="0"><tr><td height="68">
<table width="100%" height="47" border="0">
---------------------------------------------------------------------------------------------------------<br>';

echo '<strong>' . $rows['name'] . ' (' . $rows['classification'] . ')
<br></strong>';
foreach (explode(',', $rows['screeningTime']) as $time) { ?>
<label>
<input type="radio" name="time[<?php echo $rows['name']; ?>]"
value="<?php echo $time; ?>">
<?php echo $time; ?>&nbsp;&nbsp;&nbsp;
</label>
<?php } ?>
<?
}


}
?>

[/PHP]

<input name="request" type="submit" id="request" value="Submit Request"  onclick="formSubmit(document.movieList)">
 

[acoder]

To validate a form, use the onsubmit event:
[HTML]<form name="..." action="..." onsubmit="return formSubmit(this);">[/HTML] In formSubmit(), returnValue should be set to true or false. If the validation passes, return true. If it fails, return false.