determine leap year, javascript

[ballygowanboy]

hi, i need a javascript that determines if a year is a leap year or not, by putting the year in a text field and hitting a submit button.

i'm fairly new to all this, so would appriciate the help, ta.

[gits]

hi ...

have a look at the following thread:

http://www.thescripts.com/forum/thread663618.html

kind regards

[ballygowanboy]

hi ...

have a look at the following thread:

http://www.thescripts.com/forum/thread663618.html

kind regards

thanks gits, i'm using your code in that example, which works grand.

can you tell me what the % sign does? year % 100

also, what does flag mean?

also, in the form submit button, can you explain this code,

onclick="leapYear(document.getElementById('year'). value);"

[gits]

hi ...

it's not my code ;) ... only helped to get it to work ... 3 things to mention:

1. % is the modulus-operator - have a look here

2. flag is a simple variable in that script ;) doesn't mean anything ... the poster there called it that way ...

3. consider to use the solution that jsakalos provided there ... it's shorter probably better then the other solution

kind regards

[ballygowanboy]

hi ...

it's not my code ;) ... only helped to get it to work ... 3 things to mention:

1. % is the modulus-operator - have a look here

2. flag is a simple variable in that script ;) doesn't mean anything ... the poster there called it that way ...

3. consider to use the solution that jsakalos provided there ... it's shorter probably better then the other solution

kind regards

i think i'd better get my head around a basic way, before i use jsakalos's version.

i have to do this in php.

here's what i understand, the user has to enter a year, this number has to be disivable by 4 with no remainders, if the year ends in a 00 it's not a leap year, unless it's every 400 years, then it is.

here's my own code so far,

i'm parsing this through a form.....

<?php
 
 
$leap = x % 100;
 
 
 
$x = $_POST["txtRequest"]; 
 
if ($leap == 0)
 
{
        echo("this is a leap year");
}
 
 
else 
{ 
 
        echo("this is not a leap year");
}
 
?>
 
 

at the moment, i'm only dividing the number by 4, and seeing if the remainder is 0, this should work right? but it doesn't.

i need to get that working, and then add 2 other variables?

also, why doesn't flay have a var before it, if it is a variable?

[ballygowanboy]

ok, i was sure this would work........ but i'm just getting an error, am i close with this one, or am i way off?

<?php
 
 
$leap = $x;
 
 
 
$x = $_POST["year"]; 
 
if ($leap == (($x%100) == 0 || ($x%400) == 0  || ($x%4) == 0)
 
{
        echo("this is a leap year");
}
 
 
else 
{ 
 
        echo("this is not a leap year");
}
 
?>

[epots9]

ok, i was sure this would work........ but i'm just getting an error, am i close with this one, or am i way off?

<?php
 
 
$leap = $x;
 
 
 
$x = $_POST["year"]; 
 
if ($leap == (($x%100) == 0 || ($x%400) == 0  || ($x%4) == 0)
 
{
        echo("this is a leap year");
}
 
 
else 
{ 
 
        echo("this is not a leap year");
}
 
?>

what does the error say?

and i thought u wanted to do this with javascript...thats php?

[ballygowanboy]

what does the error say?

and i thought u wanted to do this with javascript...thats php?

i have to do it in javascript and php.......... ok here's my latest attempt, in php........

<?php
 
 
$leap = $x;
 
 
 
$x = $_POST["year"];
 
if ($leap == (($x%100) == 0 || ($x%400) == 0 || ($x%4) == 0)
 
{
echo("this is a leap year");
}
 
 
else
{
 
echo("this is not a leap year");
}
 
?>

i'm not getting any errors, but basicly every year is a leap year :/

can you comment on this code, tell me if i'm anywhere close, if i'm on the right track....... i know there's probably a cleaner faster way to do this, but i'm just trying to understand conditionals.

basicly, i'm trying to say in the code, if x is divided by 4, 100 or 400, and you get a module with nothing left over, it's a leap year.

am i making any sence?

[epots9]

i have to do it in javascript and php.......... ok here's my latest attempt, in php........

<?php
 
 
$leap = $x;
 
 
 
$x = $_POST["year"];
 
if ($leap == (($x%100) == 0 || ($x%400) == 0 || ($x%4) == 0)
 
{
echo("this is a leap year");
}
 
 
else
{
 
echo("this is not a leap year");
}
 
?>

i'm not getting any errors, but basicly every year is a leap year :/

can you comment on this code, tell me if i'm anywhere close, if i'm on the right track....... i know there's probably a cleaner faster way to do this, but i'm just trying to understand conditionals.

basicly, i'm trying to say in the code, if x is divided by 4, 100 or 400, and you get a module with nothing left over, it's a leap year.

am i making any sence?

this is it:
[php]
$x = $_POST["year"];

if (($x%4) == 0)
{
echo("this is a leap year");
}
else
{
echo("this is not a leap year");
}
[/php]

there is nothing other that that.

[ballygowanboy]

this is it:
[php]
$x = $_POST["year"];

if (($x%4) == 0)
{
echo("this is a leap year");
}
else
{
echo("this is not a leap year");
}
[/php]

there is nothing other that that.

ok, a little help from a guy in work, and here it is!

 
<?php
 
$x = $_POST["year"];
 
 
$leap = $x;
 
 
if ( ( ($x % 4 == 0) && ($x % 100 !=0) )  ||  ($x % 400 == 0) )
 
{
        echo("this is a leap year");
}
 
 
else 
{ 
 
        echo("this is not a leap year");
}
 
?>

my brain's still a bit fuzzy over the whole leap year thing, but i'm starting to get the whole conditional thing, oh, and i know how modules work!

[epots9]

inside your if, y don't u just use '%4'? y do u need '%100' or '%400'?

if it returns 0 its a leap year, if it returns anything else its not a leap year.

[ballygowanboy]

inside your if, y don't u just use '%4'? y do u need '%100' or '%400'?

if it returns 0 its a leap year, if it returns anything else its not a leap year.

ye, you need the other 2, as years ending in 00 is not a leap year, except for every 400 years.

[mrhoo]

If a year is evenly divisibly by 100 it is not a leap year, unless it is also evenly divisibly by 400. 1900 was not a leap year, 2000 was.