get characters before and after "token"?

[Alan]

I am kind of new to javascript, I am not sure if there is direct support
for "tokens" in the sense that they are characters that mark places in a
string.

For example if I had

var mystring = "12345:abcde";

and I wanted to consider the colon ":" in the middle a token, how would I
define a new variable that is everything that comes before it (12345)? How
about for after it (abcde)?

I am sorry if this is a stupid noob question.

[d d]

Alan wrote:

I am kind of new to javascript, I am not sure if there is direct support
for "tokens" in the sense that they are characters that mark places in a
string.

For example if I had

var mystring = "12345:abcde";

and I wanted to consider the colon ":" in the middle a token, how would I
define a new variable that is everything that comes before it (12345)? How
about for after it (abcde)?

I am sorry if this is a stupid noob question.

If you knew for a fact that there was a : in the
string then you could do this:

alert(mystring.substring(0,mystring.indexOf(":"))) ; //12345
alert(mystring.substring(mystring.indexOf(":")+1)) ; //abcde

or you could split it into an array:

var newarray = mystring.split(":");
alert(newarray[0]); //12345
alert(newarray[1]); //abcde

~dd

[Alan]

Hi,

Thanks very much that works a treat. I have a follow up question now.
Sort of the inverse.

If I have this:

var mystring = "For $100 more (optional) we can upgrade you ($150.00)";

How can I extract the number 150.00?

In this case and the others I need to work with the numerical value is
ALWAYS between the two characters '($' and the single ')' and that part
of the string is ALWAYS at the end. ($150.00) or whatever it is is
always the last characters in the string if that helps.

I have been trying various things with substring and indexof and
lastindex of but I can't quite figure it out.

d d <no*****@please.netwrote in
news:f6*************@news.t-online.com:

Alan wrote:

>I am kind of new to javascript, I am not sure if there is direct
support for "tokens" in the sense that they are characters that mark
places in a string.

For example if I had

var mystring = "12345:abcde";

and I wanted to consider the colon ":" in the middle a token, how
would I define a new variable that is everything that comes before it
(12345)? How about for after it (abcde)?

I am sorry if this is a stupid noob question.

If you knew for a fact that there was a : in the
string then you could do this:

alert(mystring.substring(0,mystring.indexOf(":"))) ; //12345
alert(mystring.substring(mystring.indexOf(":")+1)) ; //abcde

or you could split it into an array:

var newarray = mystring.split(":");
alert(newarray[0]); //12345
alert(newarray[1]); //abcde

~dd

[d d]

Alan wrote:

If I have this:
var mystring = "For $100 more (optional) we can upgrade you ($150.00)";
How can I extract the number 150.00?
In this case and the others I need to work with the numerical value is
ALWAYS between the two characters '($' and the single ')' and that part
of the string is ALWAYS at the end. ($150.00) or whatever it is is
always the last characters in the string if that helps.
I have been trying various things with substring and indexof and
lastindex of but I can't quite figure it out.

This should work:

var mystring="For $100 (optional) blah ($150.00)";
var start=mystring.lastIndexOf("$")+1;
var end=mystring.lastIndexOf(")");
var val=mystring.substring(start,end);
~dd

[Evertjan.]

d d wrote on 30 jun 2007 in comp.lang.javascript:

Alan wrote:

>If I have this:
var mystring = "For $100 more (optional) we can upgrade you ($150.00)";
How can I extract the number 150.00?
In this case and the others I need to work with the numerical value is
ALWAYS between the two characters '($' and the single ')' and that part
of the string is ALWAYS at the end. ($150.00) or whatever it is is
always the last characters in the string if that helps.
I have been trying various things with substring and indexof and
lastindex of but I can't quite figure it out.

This should work:

var mystring="For $100 (optional) blah ($150.00)";
var start=mystring.lastIndexOf("$")+1;
var end=mystring.lastIndexOf(")");
var val=mystring.substring(start,end);

Regex:

var myString = 'For $100 (optional) blah ($150.00)';
var result = myString.replace(/^.*?\(\$(.*)?\)$/,'$1');

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[d d]

Evertjan. wrote:

d d wrote on 30 jun 2007 in comp.lang.javascript:

>var mystring="For $100 (optional) blah ($150.00)";
var start=mystring.lastIndexOf("$")+1;
var end=mystring.lastIndexOf(")");
var val=mystring.substring(start,end);

Regex:
var myString = 'For $100 (optional) blah ($150.00)';
var result = myString.replace(/^.*?\(\$(.*)?\)$/,'$1');

Cool!! I always try to avoid using Regular expressions.
Mostly because (a) they're impossible for humans to
understand, and (2) I'm a human ;-)

If you're an experienced regexp'er then they're cool.
But don't expect anyone else to understand them. Of
course that in itself can be good for job security ;-)

~dd

[Evertjan.]

d d wrote on 30 jun 2007 in comp.lang.javascript:

Evertjan. wrote:

>d d wrote on 30 jun 2007 in comp.lang.javascript:

>>var mystring="For $100 (optional) blah ($150.00)";
var start=mystring.lastIndexOf("$")+1;
var end=mystring.lastIndexOf(")");
var val=mystring.substring(start,end);

Regex:
var myString = 'For $100 (optional) blah ($150.00)';
var result = myString.replace(/^.*?\(\$(.*)?\)$/,'$1');

Cool!! I always try to avoid using Regular expressions.
Mostly because (a) they're impossible for humans to
understand, and (2) I'm a human ;-)

If you're an experienced regexp'er then they're cool.
But don't expect anyone else to understand them. Of
course that in itself can be good for job security ;-)

Do you mean I should ask money for it?

Regex is very powerfull, fits nicely in javascipt
and can be learned in 2 nights.

I would advice you to spend the time.

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[d d]

Evertjan. wrote:

Regex is very powerfull, fits nicely in javascipt
and can be learned in 2 nights.
I would advice you to spend the time.

Oh yeah, I've done some regexp stuff. I made an
Ant+XML script that I use to minimize/obfuscate
some JS files. But in that case the program to
do that job without regexp would have been a
nightmare. I needed a list of the commands to do
it though :-)

~dd

[ron.h.hall]

On Jun 30, 8:41 am, "Evertjan." <[e-mail]:

d d wrote on 30 jun 2007 in comp.lang.javascript:

Evertjan. wrote:

d d wrote on 30 jun 2007 in comp.lang.javascript:
var mystring="For $100 (optional) blah ($150.00)";
var start=mystring.lastIndexOf("$")+1;
var end=mystring.lastIndexOf(")");
var val=mystring.substring(start,end);
Regex:
var myString = 'For $100 (optional) blah ($150.00)';
var result = myString.replace(/^.*?\(\$(.*)?\)$/,'$1');

Cool!! I always try to avoid using Regular expressions.
Mostly because (a) they're impossible for humans to
understand, and (2) I'm a human ;-)

If you're an experienced regexp'er then they're cool.
But don't expect anyone else to understand them. Of
course that in itself can be good for job security ;-)

Do you mean I should ask money for it?

Regex is very powerfull, fits nicely in javascipt
and can be learned in 2 nights.

I would advice you to spend the time.

That's good advice. However, "2 nights" may not suffice.

var result = myString.replace(/^.*?\(\$(.*)?\)$/,'$1');

will produce an incorrect result, for example, with:

var myString = 'For $100 (optional) ($300.00) blah ($150.00)';

There are a number of things wrong in the construction of the regular
expression you have proposed, but in particular "?" seems to be
misused or misplaced, or both.

Great care is always required in composing regular expressions, and
even those with a high level of competence in the area need to
carefully test that they produce the desired result. They are
extremely useful, but they are in my experience, not at all easy to
master and use effectively.

var m;
if ( m = myString.match( /^.*\(\$(\d+\.\d{2})\)$/ ) ) {
alert( "Matched: " + m[1] );
}

may serve better.

--
../rh

[ron.h.hall]

On Jun 30, 1:49 pm, [e-mail] wrote:

>
var m;
if ( m = myString.match( /^.*\(\$(\d+\.\d{2})\)$/ ) ) {
alert( "Matched: " + m[1] );

}

may serve better.

And since it's now used in a match rather than replace, the regular
expression can be further simplified to:

/\(\$(\d+\.\d{2})\)$/

--
../rh