Dynamic Variable ?

[Leon]

Hi all,

hopefully someone knows the answer to this one !

Im trying to use something like this...

>var riders = dropriders.split(",");

for (x in riders)
{
var shebang = strvalue.concat("rider" , riders[x]);
value += rPrice[document.myteam.shebang.value];
}

dropriders can be from one to ten elements looking something like --1,2,6

Therefore in the value += line, i would want shebang to be replaced by
rider1, rider2, rider6.

Any thoughts ?

Thanks in advance,

Leon

[RobG]

On May 11, 8:10 am, Leon <[e-mail]:

Hi all,

hopefully someone knows the answer to this one !

The FAQ does...

Im trying to use something like this...

>var riders = dropriders.split(",");
>>
>for (x in riders)
>{
>var shebang = strvalue.concat("rider" , riders[x]);
>value += rPrice[document.myteam.shebang.value];
>}

dropriders can be from one to ten elements looking something like --1,2,6

Therefore in the value += line, i would want shebang to be replaced by
rider1, rider2, rider6.

Any thoughts ?

<URL: http://www.jibbering.com/faq/#FAQ4_39 >
--
Rob

[Dr J R Stockton]

In comp.lang.javascript message <4643986b$0$8711$ed2619ec@ptn-nntp-
reader02.plus.net>, Thu, 10 May 2007 23:10:51, Leon
<le**@dontcallmeeeore.co.ukposted:

>>var shebang = strvalue.concat("rider" , riders[x]);
value += rPrice[document.myteam.shebang.value];

>Therefore in the value += line, i would want shebang to be replaced by
rider1, rider2, rider6.

FAQ 4.25 provides the necessary clue. FAQ 4.39 is better. They should
be merged, or at least consecutive.

The example in 4.39, while valid, is pointless; there should also be an
example with a variable string, such as "Item"+N. I can see no point in
using bracket notation where the string is a constant known at code-
writing time.

It's a good idea to read the newsgroup c.l.j and its FAQ. See below.

--
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