Form with two submit buttons

1,584 Expert 1GB

I need to print A when click on Button A and and print B for button B.
but for both button it gives A.
[HTML]<html>
<head>
<script language="JavaScript" type="text/javascript">
function AB()
{
if(document.testform.btn_a)
{
alert("A");
return false;
}
if(document.testform.btn_b)
{
alert("B");
return false;
}
}
</script>

</head>

<body>
<form action="next.php" method="post" name="testform" onsubmit="return AB();">
<input name="btn_a" type="submit" value=" A " />
<input name="btn_b" type="submit" value=" B " />
</form>
</body>
</html>
[/HTML]

May 9 '07 #1

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1500

acoder

16,027

Expert Mod 8TB

Are you going to submit the form to a server script (Is the return false just for testing)? Usually you can use the server-side language to detect which button has been clicked.

You're checking for btn_a which exists so it will always return true. Try using onclick and setting a variable to 'a' or 'b', then testing for that in the onsubmit.

May 9 '07 #2

ak1dnar

1,584

Expert 1GB

Yes this is for testing only.
in my actual form there are two submit buttons. and there is a server side script.

for submit_1 the number of rows will update with the server side script.
for submit_2 the form content(User Details) will pass to the same script for processing.(Except number of rows text input).

that is working fine.

but when submit User details (Not the row numbers) i need to run the JS to validate user inputs. the problem is for for rows updating button also the JS is executing.

May 10 '07 #3

pbmods

5,821

Expert 4TB

but when submit User details (Not the row numbers) i need to run the JS to validate user inputs. the problem is for for rows updating button also the JS is executing.

Try making the form action your validation function instead. See this post:
http://www.thescripts.com/forum/thread636859.html

May 10 '07 #4

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