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Problem on regular expression

If there is a unlimit long textfield, the user can type free text.
It means that the client can type
I like eating very much .

How can I using regular expression to trim the spaces to single space?

Thank you

Jun 20 '06 #1
4 1325
further example:
I like eating very much
Jun 20 '06 #2
Cylix wrote:
If there is a unlimit long textfield, the user can type free text.
It means that the client can type
I like eating very much .

How can I using regular expression to trim the spaces to single space?

Thank you

Hi,

Here is an example that matches as you described.

Regards,
Erwin Moller

------------------------

<html>
<head>

<script type="text/javascript">
function removespaces(){
var org = document.forms.testform.inp.value;

document.forms.testform.outp.value = org.replace(/ +/g , " ");
}
</script>

</head>
<body>

<form name="testform">
INPUT:
<textarea rows=4 cols=60 name="inp"></textarea>
<br>
<input type="button" onclick="removespaces();" value="replace multiple
spaces with one">

<br>
OUTPUT:
<textarea rows=4 cols=60 name="outp"></textarea>
<br>
</form>

</body>
</html>
Jun 20 '06 #3
Erwin Moller wrote on 20 jun 2006 in comp.lang.javascript:
document.forms.testform.outp.value = org.replace(/ +/g , " ");


document.forms.testform.outp.value = org.replace(/\s+/g ,' ');

Removes all kinds of white space.

\s is equivalent to [ \f\n\r\t\v].

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
Jun 20 '06 #4
"Cylix" <cy*******@gmail.com> writes:
further example:
I like eating very much
.

How can I using string.replace(regEx, '') and string.replace(regEx, '
') to have the result:
I like eating very much.

That's a more specific wish. Not only do you want to convert repeated
spaces to single ones, you also want to remove any space between words
and following punctuation, and all initial (and probably terminal)
spaces.

Might as well do it in three goes first:

string.replace(/^\s+|\s+$/g,"")
.replace(/\b\s+([^\w\s])/,"$1")
.replace(/\s+/," ")

The first replace removes initial and terminal whitespace.
The second replace removes spaces between a word boundary and
a non-word/non-space character.
The third replace converts single spaces to multiple spaces.

You can probably make a single regexp that does it all, but you'll
have to be inventive (and probably use advanced features like
lookahead) since you will want to replace with different strings
in each of the three cases.

But here is one attempt:

/^\s+|\s+$|\b\s+(?=[^\w\s])|\s+(?=\s)/g

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleDOM.html>
'Faith without judgement merely degrades the spirit divine.'
Jun 20 '06 #5

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