I am weak when it comes to regexp but hoped someone might know in this case.
I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter
to be replaced would be a parameter passed to a function. Here is what I
have so far:
function refresh(item) {
current = document.location.href;
if(current.match(item.name+'='))
//pseudo code here
//current.replace(item.name regexp , '');
return (current + "&" + item.name + "=" + item.value);
This function would be fired like this :
All <input type="radio" name="show" value="all"
onclick="document.location=refresh(this);">
Mine <input type="radio" name="show" value="mine"
onclick="document.location=refresh(this);">
Any suggestions are appreciated!
-S 13 1813
Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript : I am weak when it comes to regexp but hoped someone might know in this case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter to be replaced would be a parameter passed to a function.
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
alert(str)
str = str.replace(/sort=[^&]*&?/,'')
alert(str)
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
Evertjan. wrote on 26 dec 2005 in comp.lang.javascript : Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript:
I am weak when it comes to regexp but hoped someone might know in this case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter to be replaced would be a parameter passed to a function.
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
alert(str)
str = str.replace(/sort=[^&]*&?/,'')
alert(str)
Sorry, incorrect, the send button was pressed too soon, try this:
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
str = str.replace(/&?sort=[^&]*/,'')
alert(str)
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello'
str = str.replace(/&?sort=[^&]*/,'')
alert(str)
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
in article Xn********************@194.109.133.242, Evertjan. at ex**************@interxnl.net wrote on 12/26/05 8:19 AM: Evertjan. wrote on 26 dec 2005 in comp.lang.javascript:
Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript:
I am weak when it comes to regexp but hoped someone might know in this case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter to be replaced would be a parameter passed to a function.
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
alert(str)
str = str.replace(/sort=[^&]*&?/,'')
alert(str)
Sorry, incorrect, the send button was pressed too soon, try this:
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
str = str.replace(/&?sort=[^&]*/,'')
alert(str)
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello'
str = str.replace(/&?sort=[^&]*/,'')
alert(str)
I appreciate this. It almost perfect. My ISP apparently sends fast but
receives SLOW. I saw the response on google over 30 minutes ago. Anyhow, I
have been playing with it and have found a small difficulty. I am trying to
place a variable into the reg exp as you may have seen in my formula. I
tried all sorts of variances like
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello'
item="sort";
//str = str.replace(/&?sort=[^&]*/,'')
//str2 = eval("/&?" + item + "=[^&]*/");
str3 = /&?(item)=[^&]*/;
alert(str3);
//str2 = new RegExp(str3, "gi");
str = str.replace(str3,'')
alert(str)
How do I get the evaluated variable into the regexp?
-S
On 26/12/2005 16:27, Phat G5 (G3) wrote:
[snip] str = 'something.lasso?blah=blah&blah2=blah2&sort=hello' item="sort";
//str = str.replace(/&?sort=[^&]*/,'')
[snip]
How do I get the evaluated variable into the regexp?
str.replace(new RegExp('&?' + item + '=[^&]*'), '');
Mike
--
Michael Winter
Prefix subject with [News] before replying by e-mail.
Michael Winter wrote: On 26/12/2005 16:27, Phat G5 (G3) wrote:
[snip]
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello' item="sort";
//str = str.replace(/&?sort=[^&]*/,'')
[snip]
How do I get the evaluated variable into the regexp?
str.replace(new RegExp('&?' + item + '=[^&]*'), '');
Mike
-- Michael Winter Prefix subject with [News] before replying by e-mail.
I am not able to get that to work. It does not evalueate it properly
for some reason. Did you by chance test it out? I tried it in Firefox
and Safari.
-S
On 26/12/2005 17:05, Steffan wrote: Michael Winter wrote:
[snip] str.replace(new RegExp('&?' + item + '=[^&]*'), '');
[snip]
I am not able to get that to work. It does not evalueate it properly for some reason. Did you by chance test it out? I tried it in Firefox and Safari.
Yes, it works in IE, Firefox, and Opera. Even NN4.
Care to post the code you've been using?
Mike
--
Michael Winter
Prefix subject with [News] before replying by e-mail.
Michael Winter wrote: On 26/12/2005 16:27, Phat G5 (G3) wrote: str = 'something.lasso?blah=blah&blah2=blah2&sort=hello' item="sort";
//str = str.replace(/&?sort=[^&]*/,'') How do I get the evaluated variable into the regexp?
str.replace(new RegExp('&?' + item + '=[^&]*'), '');
Perhaps you meant
str.replace(new RegExp('[&?]' + item + '=[^&]*'), '');
PointedEars
Actually I figured it out. i did an exact copy and paste and didnt do
str=str.replace...
My bad! Thanks for the help on this one. I've had to use google to do
this since my isp's refresh rate on the usnet gropus are a bit slow
today.
-S
Evertjan. wrote: str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3' str = str.replace(/&?sort=[^&]*/,'')
Fails with:
str =
'something.lasso?blah=blah&resort=XXX&blah2=blah2& sort=hello&blah3=blah3'
So, I would recommend:
str = str.replace(/[&?]sort=[^&]*/,'')
--
Matt Kruse http://www.JavascriptToolbox.com http://www.AjaxToolbox.com
Matt Kruse wrote on 26 dec 2005 in comp.lang.javascript : Evertjan. wrote: str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3' str = str.replace(/&?sort=[^&]*/,'') Fails with:
str = 'something.lasso?blah=blah&resort=XXX&blah2=blah2& sort=hello&blah3
=blah3' So, I would recommend:
str = str.replace(/[&?]sort=[^&]*/,'')
Good work, Mat.
combined with the more general Q,
and because "item" is a reserved word:
str = str.replace(new RegExp('[&?]' + myItem + '=[^&]*'), '');
==================
Test:
myItem = 'sort'
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3'
str = str.replace(new RegExp('[&?]' + myItem + '=[^&]*'), '');
alert(str)
str = 'something.lasso?blah=blah&blah2=blah2&sort=hello'
str = str.replace(new RegExp('[&?]' + myItem + '=[^&]*'), '');
alert(str)
str = 'something.lasso?sort=hello&blah2=blah2&asdf=bello '
str = str.replace(new RegExp('[&?]' + myItem + '=[^&]*'), '');
alert(str)
str = 'something.lasso?blah=blah&blah2=blah2&qwersort=he llo'
str = str.replace(new RegExp('[&?]' + myItem + '=[^&]*'), '');
alert(str)
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
Matt Kruse wrote: Evertjan. wrote: str = 'something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3' str = str.replace(/&?sort=[^&]*/,'')
Fails with:
str = 'something.lasso?blah=blah&resort=XXX&blah2=blah2& sort=hello&blah3=blah3'
So, I would recommend:
str = str.replace(/[&?]sort=[^&]*/,'')
I would not, because it would also remove the leading `?' if the `sort'
name-value pair was at the first position, which is why I canceled my other
reply. Try
str = str.replace(/((\?)|&)sort(=[^&]*)?/, '$2');
instead. With a variable that would be
str = str.replace(new RegExp('((\\?)|&)' + item + '(=[^&]*)?'), '$2');
(provided that item does not contain any RegExp special characters.)
PointedEars
Thomas 'PointedEars' Lahn wrote on 26 dec 2005 in comp.lang.javascript : str = str.replace(/[&?]sort=[^&]*/,'') I would not, because it would also remove the leading `?' if the `sort' name-value pair was at the first position, which is why I canceled my other reply. Try
str = str.replace(/((\?)|&)sort(=[^&]*)?/, '$2');
instead. With a variable that would be
str = str.replace(new RegExp('((\\?)|&)' + item + '(=[^&]*)?'), '$2');
That gives a ?& for ...?sort=qwe&...
try:
re = new RegExp('&?' + myItem + '(=[^&]*)?')
str = str.replace(re,'').replace(/\?&/,'?');
(provided that item does not contain any RegExp special characters.)
Mmm, yes ....
couldn't we prepare myItem [item is reserved]?
myItem = '\'+myItem.split(''),join('\')
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)
On 2005-12-26, Phat G5 (G3) <no****@noone.com> wrote: I am weak when it comes to regexp but hoped someone might know in this case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter to be replaced would be a parameter passed to a function. Here is what I have so far:
something like this?
function refresh(item)
{
var s=location.search.replace(/&sort=[^&]*&/,"&sort="+item.value+'&');
location.search=s;
return true;
}
Bye.
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