tag id name

[GTi]

I have several <div id='DivNumber1'> on my page.
the Id can be a random number between 1 and 65535.

I need a script where I can get all div tags and check if the ID is
DivNumber.

This does not work:
if(document.getElementById)
{
var ar = document.getElementsByTagName("DIV");
for (var i=0; i<ar.length; i++)
{
s1 = new String(ar[i].id);
if(s1.search('GroupItem')>=0) ar[i].style.display = "none";
}
}

[GTi]

Whops: Bugfix:

if(document.getElementById)
{
var ar = document.getElementsByTagName("DIV");
for (var i=0; i<ar.length; i++)
{
s1 = new String(ar[i].id);
if(s1.search('DivNumber')>=0) ar[i].style.display = "none";
}
}

[Evertjan.]

GTi wrote on 13 dec 2005 in comp.lang.javascript:

Whops: Bugfix:

if(document.getElementById)
{
var ar = document.getElementsByTagName("DIV");
for (var i=0; i<ar.length; i++)
{
s1 = new String(ar[i].id);
if(s1.search('DivNumber')>=0) ar[i].style.display = "none";
}
}

Simplified:

if(document.getElementsByTagName) {
var ar = document.getElementsByTagName("DIV");
for (var i=0; i<ar.length; i++)
if (/DivNumber/.test(ar[i].id))
ar[i].style.display = "none";
}

--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[GTi]

Evertjan,

what does / is syntax for:
/DivNumber/.test()
in
if (/DivNumber/.test(ar[i].id))
???

[Evertjan.]

GTi wrote on 13 dec 2005 in comp.lang.javascript:

Evertjan,

what does / is syntax for:
/DivNumber/.test()
in
if (/DivNumber/.test(ar[i].id))

/DivNumber/ is a regular expression.
regex test tests the string and returns true or false.
You don't need to setup an object here.

--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

[Thomas 'PointedEars' Lahn]

GTi wrote:

Whops: Bugfix:
Not really.
if(document.getElementById)
{
var ar = document.getElementsByTagName("DIV");
Although both methods are defined in the same DOM Level, support
for Document::getElementById() does not imply support for
Document::getElementsByTagName() in an implementation, so you
should also feature-test the latter on run-time.

<URL:http://PointedEars.de/scripts/test/whatami>, § 2.
for (var i=0; i<ar.length; i++)
Instead

for (var i = ar.length; i--;)

since order does not matter; if it does matter, use

for (var i = 0, len = ar.length; i < len; i++)
{
s1 = new String(ar[i].id);
Java != JavaScript. You do not need to create a String object in order
to work with string values or to apply properties of String.prototype.
For type conversion to string, use the String(noString) function or
the toString(noString).method. And since the value of the `id'
attribute/property already is a string, there is no type conversion
necessary.
if (s1.search('DivNumber')>=0) ar[i].style.display = "none";
Instead:

var o = ar[i];
if (o.id.indexOf('DivNumber') >= 0)
{
if (typeof o.style != "undefined"
&& typeof o.style.display != "undefined")
{
o.style.display = "none";
}
}
}

HTH

PointedEars

[GTi]

I have a menu structure with several <div id=DivNumberxxxx> that is
blocks of menu groups. But I also have other <div id=whatever> sections
that I don't want to hide.
But it still don't work - it hide <div id=whatever> also :

I have this function:

function MainMenuGroupExpand(obj)
{
if(document.getElementsByTagName)
{
var el = document.getElementById(obj);
var ar =
document.getElementById("MenuGroup").getElementsBy TagName("DIV");
if(el.style.display == "none")
{
for (var i=ar.length; i--;)
{
var o = ar[i];
if (o.id.indexOf('DivNumber') == 0)
{
if((typeof o.style != "undefined") && (typeof o.style.display
!= "undefined"))
{
o.style.display = "none";
}
}
}
el.style.display = "block";
}
}
}

[GTi]

Yes - it does work.
It was a spelling error by me.
MenuGroup -> MenyGroup
Sorry and thanks for helping me :)

[Thomas 'PointedEars' Lahn]

GTi wrote:

I have a menu structure with several <div id=DivNumberxxxx> that is
blocks of menu groups. But I also have other <div id=whatever> sections
that I don't want to hide.
But it still don't work - it hide <div id=whatever> also :

I have this function:

function MainMenuGroupExpand(obj)
{
if(document.getElementsByTagName) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ {
var el = document.getElementById(obj); ^^^^^^^^^^^^^^^^^^^^^^^^ var ar =
document.getElementById("MenuGroup").getElementsBy TagName("DIV"); ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^ if(el.style.display == "none")
{
for (var i=ar.length; i--;)
{
var o = ar[i];
if (o.id.indexOf('DivNumber') == 0) ^^
Have you /really/ read _and_ understood what I posted?
[...]

PointedEars

[GTi]

Hmm...
Looks like I have overlooked something here.
Yes I have readed it but I admit that I do not understand it 100%

if (o.id.indexOf('DivNumber') == 0)

It is always the beginning of the tag name. It will ignore
id='otherDivNumer'

I must try to understand what the other 'red markers' are.

[Thomas 'PointedEars' Lahn]

GTi wrote:

> if (o.id.indexOf('DivNumber') == 0) It is always the beginning of the tag name.

You mean the attribute value.
It will ignore id='otherDivNumer'
Then this line is OK so.
I must try to understand what the other 'red markers' are.

In case of questions, do not hesitate to ask.

But please learn how to quote on Usenet before:
<URL:http://jibbering.com/faq/faq_notes/pots1.html#ps1Post>
PointedEars

[Jasen Betts]

On 2005-12-13, GTi <tu****@gmail.com> wrote:

I have several <div id='DivNumber1'> on my page.
the Id can be a random number between 1 and 65535.

I need a script where I can get all div tags and check if the ID is
DivNumber.

var ar = document.getElementsByTagName("DIV");

how about this?

var ar = document.getElementsByTagName("div");

--

Bye.
Jasen