Changing 'selected' Option in Select Dropdown before Submit

Monty

I use a SELECT dropdown as the nav interface for jumping to a chosen
page number. When I setup up the SELECT element on the page, I want to
show the user the current page number they are on, so, I put "selected"
next to the page number, as shown below:

-------------------------------

<form name="pick" method="post" action="showit.php">
<select name="pggo"
onChange="this.options[this.selectedIndex].selected;document.pick.submit();">
<option value="1">1</option>
<option value="2" selected>2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
</select>
</form>

-------------------------------

The problem is that no matter what page number is chosen from the
dropdown, the passed value is always "2", because that's the "selected"
value above.

Is there any Javascript that I can add to the onChange statement above
that will change the 'selected' value from the current page number to
the one chosen by the user? I've tried a bunch of things, but, 2 is the
value that seems to always get passed. I'm not sure how to change the
selected value to the one chosen from the dropdown. Am I close with the
above code, or way off base?

Any help is much appreciated! I've spent about 4 hours searching and
trying to find out how to do this, but, nothing seems to work. Maybe
it's not possible?

Thanks.

Nov 23 '05 #1

Danny

Your plight seem to be with PHP, not with js, so, check in your PHP
script instead.

Danny

Nov 23 '05 #2

Jasen Betts

On 2005-11-20, Monty <mo****@hotmail.com> wrote:

I use a SELECT dropdown as the nav interface for jumping to a chosen
page number. When I setup up the SELECT element on the page, I want to
show the user the current page number they are on, so, I put "selected"
next to the page number, as shown below:

-------------------------------

<form name="pick" method="post" action="showit.php">
<select name="pggo"
onChange="this.options[this.selectedIndex].selected;document.pick.submit();">
<option value="1">1</option>
<option value="2" selected>2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
</select>
</form>

-------------------------------

The problem is that no matter what page number is chosen from the
dropdown, the passed value is always "2", because that's the "selected"
value above.
Add onchange to each of the options?

aboce you say:
this.options[this.selectedIndex].selected

this part does nothing, what is it supposed to do?

Bye.
Jasen

Nov 23 '05 #3