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# Difference in months

 P: n/a I was hoping someone could help me with this.. I'm not very familiar with javascript but I'm pretty sure it can help me with what I need to accomplish. I've tried piecing several pieces of script together but I've had no luck so far. What I need to do is have a user input for Year, Month and day (preferably drop down) and compare the input to today's date and display the difference in months. Any help with this would be appreciated. Thanks! Jul 23 '05 #1
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 P: n/a br********@gmail.com wrote: I was hoping someone could help me with this.. I'm not very familiar with javascript but I'm pretty sure it can help me with what I need to accomplish. I've tried piecing several pieces of script together but I've had no luck so far. What I need to do is have a user input for Year, Month and day (preferably drop down) and compare the input to today's date and display the difference in months. A good start is to have a read here: -- RobG Jul 23 '05 #2

 P: n/a wrote in message news:11**********************@g14g2000cwa.googlegr oups.com...I was hoping someone could help me with this.. I'm not very familiar with javascript but I'm pretty sure it can help me with what I need to accomplish. I've tried piecing several pieces of script together but I've had no luck so far. What I need to do is have a user input for Year, Month and day (preferably drop down) and compare the input to today's date and display the difference in months. I think you'll need to be more specific in terms of your requirements. Assuming today is June 1. If I enter June 2, how many "months" different is that from today? 0 months different? 0.0333333... months (1 day divided by the 30 days in this month) different? How about if I enter July 31? Is that 1 month different, 2 months different (since July 31 is more than twice the number of days in June away from June 1) or 2.032258064516129032258064516129032 months different (2 times 30 days in June + 1/31 days in July)? I'm not trying to be difficult, when you say "how many months away is this day from this other day" these are the types of real things you need to think about. Anyway, if you just want it as an integer where a day in the same month is 0 months and any day in any other month is the number of months different, then it's (something like): But you've still got some problems... the date the user enters may not be in a format that new Date() understands, so you'll need to parse it and ensure that it is. -- Grant Wagner comp.lang.javascript FAQ - http://jibbering.com/faq Jul 23 '05 #3

 P: n/a I'll give it a shot. Thanks for your help! Jul 23 '05 #4

 P: n/a br********@gmail.com wrote: I was hoping someone could help me with this.. I'm not very familiar with javascript but I'm pretty sure it can help me with what I need to accomplish. I've tried piecing several pieces of script together but I've had no luck so far. What I need to do is have a user input for Year, Month and day (preferably drop down) and compare the input to today's date and display the difference in months. Any help with this would be appreciated. Consider that a month is an imprecise measurement, here in NY there are at least 6 different month "lengths". And this disregards year end tweakings of the "atomic" clock. Mick Jul 23 '05 #5

 P: n/a JRS: In article , dated Wed, 1 Jun 2005 15:39:17, seen in news:comp.lang.javascript, Grant Wagner posted :Anyway, if you just want it as an integer where a day in the same monthis 0 months and any day in any other month is the number of monthsdifferent, then it's (something like): (anotherDay.getFullYear() - today.getFullYear()) * 12 + (anotherDay.getMonth() - today.getMonth()) One can also calculate an "Absolute Month Number" like function AWM(Y, M) { return Y*12+M } and then subtract. It's numerically equivalent, and less efficient; but the concept can be helpful in more complicated cases. But you've still got some problems... the date the user enters may notbe in a format that new Date() understands, so you'll need to parse itand ensure that it is. Necessary but not sufficient. It is also necessary that new Date(), for all users, interprets it in the same way as the user expects. And that must be tested for the Nth of month M, where N != M and N < 13. In article , dated Wed, 1 Jun 2005 16:54:36, seen in news:comp.lang.javascript, Mick White posted :Consider that a month is an imprecise measurement, here in NY there areat least 6 different month "lengths". And this disregards year endtweakings of the "atomic" clock. And Lunar, Hebrew, Islamic, etc., months. Year middle tweakings are equally favoured, and have been approximately equally common. Tweakings at the end of odd quarters are also allowed, but less favoured, and have not so far been needed. There will be none at the end of this month; but the length of time since the previous leap second now is and until the next one will remain longer than it has ever been before (IIRC). -- © John Stockton, Surrey, UK. ?@merlyn.demon.co.uk Turnpike v4.00 MIME. © Web - w. FAQish topics, links, acronyms PAS EXE etc : - see 00index.htm Dates - miscdate.htm moredate.htm js-dates.htm pas-time.htm critdate.htm etc. Jul 23 '05 #6

 P: n/a Mick White wrote: br********@gmail.com wrote: Consider that a month is an imprecise measurement, here in NY there are at least 6 different month "lengths". And this disregards year end tweakings of the "atomic" clock. 6 different month lengths !! Thats beyond my schoolknowledge or are we using a different calendar in Denmark 8-) Mick Jul 23 '05 #7

 P: n/a please-answer-here wrote: Mick White wrote: Consider that a month is an imprecise measurement, here in NY there are at least 6 different month "lengths". And this disregards year end tweakings of the "atomic" clock. 6 different month lengths !! Thats beyond my schoolknowledge or are we using a different calendar in Denmark 8-) That sounds about right. 4 Obvious differences in the length of months in days and two months containing daylight savings/summer time adjustments. Richard. Jul 23 '05 #8

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