input[] array validation

[Jason Morehouse]

Hello...

I need to get the values (for validation) of a php style html input array:

<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">

The PHP faq gives an example:

variable = documents.forms[0].elements['var[]'];

http://ca3.php.net/manual/en/faq.htm...elect-multiple

But that doesn't actually work, for me.

What would be the proper way to loop through each of the upload inputs
and get the value?

Thanks,
-J
--
Jason Morehouse
Vendorama - The evolution of e-commerce
http://www.vendorama.com

[Martin Honnen]

Jason Morehouse wrote:

I need to get the values (for validation) of a php style html input array:

<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">

The PHP faq gives an example:

variable = documents.forms[0].elements['var[]'];

http://ca3.php.net/manual/en/faq.htm...elect-multiple

But that doesn't actually work, for me.

Be more specific about what happens, do you get a script error?
The access to
document.forms[0].elements['image[]']
with those inputs above being inside of the first <form> on the page
should indeed yield a collection with a length property through which
you can loop.

--

Martin Honnen
http://JavaScript.FAQTs.com/

[Mick White]

Jason Morehouse wrote:

Hello...

I need to get the values (for validation) of a php style html input array:

<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">
<input type="file" name="image[]">

The PHP faq gives an example:

variable = documents.forms[0].elements['var[]'];

http://ca3.php.net/manual/en/faq.htm...elect-multiple

But that doesn't actually work, for me.

What would be the proper way to loop through each of the upload inputs
and get the value?

if(variableLength = documents.forms[0].elements['var[]'].length);

It's not a select-multiple, its type is file, but js should provide a
collection, try it.
Mick