Another Reg Exp problem

[Larry Bud]

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas. valid input
could be

123
123,124
123,125,125
1,2,3
1,12,123

Invalid would be

123,
,123
123 124 125
123abc

TIA!

[kaeli]

In article <5d**************************@posting.google.com >,
la**********@yahoo.com enlightened us with...

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas. valid input
could be

Try
/^\d[,\d]*$/

--
--
~kaeli~
Murphy's Law #2030: If at first you don't succeed, destroy
all evidence that you tried.
http://www.ipwebdesign.net/wildAtHeart
http://www.ipwebdesign.net/kaelisSpace

[Lasse Reichstein Nielsen]

kaeli <ti******@NOSPAM.comcast.net> writes:

1) only digits
2) may have a comma
3) must not start or end with a comma

Try
/^\d[,\d]*$/

This can end with a comma. You probably mean
/^\d+(,\d+)*$/

Hmm. In fact, the original poster didn't say that the string must be
non-empty, so a more correct solution would be:
/^(\d+(,\d+)*)?$/

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleDOM.html>
'Faith without judgement merely degrades the spirit divine.'

[Lee]

Larry Bud said:

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas. valid input
could be

123
123,124
123,125,125
1,2,3
1,12,123

Invalid would be

123,
,123
123 124 125
123abc

If there must be at least two digits, then it's easy:
/^\d+[,\d]*\d$/

That's a digit at the beginning, any number of [comma or digit],
followed by a digit at the end.

If a single digit is also valid, then it's only a little more complicated:

/(^\d+[,\d]*\d$)|(^\d$)/

That's the same as above OR just one digit.

[Lee]

kaeli said:

In article <5d**************************@posting.google.com >,
la**********@yahoo.com enlightened us with...

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas. valid input
could be

Try
/^\d[,\d]*$/

That could end with a comma

[kaeli]

In article <3c**********@hotpop.com>, lr*@hotpop.com enlightened us
with...

kaeli <ti******@NOSPAM.comcast.net> writes:

1) only digits
2) may have a comma
3) must not start or end with a comma

Try
/^\d[,\d]*$/

This can end with a comma. You probably mean
/^\d+(,\d+)*$/

So close, and yet so far. :)
I'll get regex eventually.
--
--
~kaeli~
Support your local medical examiner: die strangely!
http://www.ipwebdesign.net/wildAtHeart
http://www.ipwebdesign.net/kaelisSpace

[Larry Bud]

Lee <RE**************@cox.net> wrote in message news:<c8*********@drn.newsguy.com>...

Larry Bud said:

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas. valid input
could be

123
123,124
123,125,125
1,2,3
1,12,123

Invalid would be

123,
,123
123 124 125
123abc

If there must be at least two digits, then it's easy:
/^\d+[,\d]*\d$/

That's a digit at the beginning, any number of [comma or digit],
followed by a digit at the end.

If a single digit is also valid, then it's only a little more complicated:

/(^\d+[,\d]*\d$)|(^\d$)/

That's the same as above OR just one digit.

Damn, I DID forget to add that it cannot be empty. Will this work for it as well?

What if someone enters

1,,23

There shouldn't be two commas in a row.

[Dr John Stockton]

JRS: In article <5d**************************@posting.google.com >, seen
in news:comp.lang.javascript, Larry Bud <la**********@yahoo.com> posted
at Mon, 24 May 2004 10:46:58 :

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma

So basically, a string of numbers separated with commas.

And non-empty.

So you want a digit, followed by any number, including zero, of comma-
followed-by-at-least-one-digit - and nothing else.

OK = /^(\d+)(,\d+)*$/.test(S)

Tested in
<URL:http://www.merlyn.demon.co.uk/js-valid.htm>
<URL:http://www.merlyn.demon.co.uk/js-quick.htm>

OK = /^(\d+,)*(\d+)$/.test(S)

should also do. In each case, the parentheses around just \d+ are
superfluous.

--
© John Stockton, Surrey, UK. ?@merlyn.demon.co.uk Turnpike v4.00 IE 4 ©
<URL:http://jibbering.com/faq/> Jim Ley's FAQ for news:comp.lang.javascript
<URL:http://www.merlyn.demon.co.uk/js-index.htm> jscr maths, dates, sources.
<URL:http://www.merlyn.demon.co.uk/> TP/BP/Delphi/jscr/&c, FAQ items, links.

[Thomas 'PointedEars' Lahn]

Larry Bud wrote:

Lee <RE**************@cox.net> wrote:

Larry Bud said:

Alright, I don't have time to learn all the intricacies of regular
expressions, but what I want to do is match a string that has:

1) only digits
2) may have a comma
3) must not start or end with a comma
[...]
If there must be at least two digits, then it's easy: /^\d+[,\d]*\d$/
[...]
If a single digit is also valid, then it's only a little more
complicated:

/(^\d+[,\d]*\d$)|(^\d$)/

That's the same as above OR just one digit.

Damn, I DID forget to add that it cannot be empty. Will this work for it
as well?

No.
What if someone enters

1,,23
It would be accepted using the above RegExp. /\d+/ matches "1",
/[,\d]*/ matches ",,2" and the final /\d/ matches "3" then.
There shouldn't be two commas in a row.

I think you are looking for /^(\d(,\d)?)+$/. Could be written as
/^(\d,\d|\d)+$/ as well. It remains to be discussed what of them
is more efficient.
HTH

PointedEars