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double mouseover or function

Why does this not work:

function flipon(){
if (!this.filters. flipH) this.style.filt er = 'flipH';
this.filters.fl ipH.enabled = true;
}
function flipoff(){
this.filters.fl ipH.enabled = false;
}

with this:

<IMG SRC="../graphics/romoy/bad.jpg" width=350 height=233 alt=""
border="0" onmouseover="fl ipon()" onmouseout ="flipoff()" >

This is ok:

<IMG SRC="../graphics/romoy/bad.jpg" width=350 height=233 alt=""
border="0" onmouseover="if (!this.filters. flipH) this.style.filt er =
'flipH'; this.filters.fl ipH.enabled = true;" onmouseout
="this.filters. flipH.enabled = false;">

I would like to put it in a function to use it here too:
Or how can I put two mouseovers in this:

<area shape="rect" alt="" coords="45,100, 78,123"
onMouseOver="ph oto.src='../graphics/romoy/bad.jpg'; return true;">

--

find clausen
www.photopress.dk
Jul 20 '05 #1
1 2326
Lee
find clausen said:

Why does this not work:

function flipon(){
if (!this.filters. flipH) this.style.filt er = 'flipH';
this.filters.f lipH.enabled = true;
}
function flipoff(){
this.filters.f lipH.enabled = false;
}

with this:

<IMG SRC="../graphics/romoy/bad.jpg" width=350 height=233 alt=""
border="0" onmouseover="fl ipon()" onmouseout ="flipoff()" >

Because "this" doesn't refer to the image except in the
event handler function. Your event handler needs to pass
that reference on to the functions that they call:

function flipon(thisImag e){
if (!thisImage.fil ters.flipH) thisImage.style .filter = 'flipH';
thisImage.filte rs.flipH.enable d = true;
}
function flipoff(thisIma ge){
thisImage.filte rs.flipH.enable d = false;
}

with this:

<IMG SRC="../graphics/romoy/bad.jpg" width=350 height=233 alt=""
border="0" onmouseover="fl ipon(this)" onmouseout ="flipoff(this) ">

Jul 20 '05 #2

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