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selecting an index

i use this but select the index by name??

document.form1. table_name.sele ctedIndex= 2;
what i want

document.form1. table_name.sele ctedIndex= "news";


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Oct 25 '05 #1
4 1105
Ross wrote:
i use this but select the index by name??

document.form1. table_name.sele ctedIndex= 2;

If this works, then form1 is the name or id of a form, table_name is the
name or id of a select element that is a child of form1 and it has at
least 3 option elements.

The above will select the 3rd option.

what i want

document.form1. table_name.sele ctedIndex= "news";


If the above is correct, you can't do it. An option element can't have
a name attribute, though it can have an ID.

If what you want to do is select the option with either text or value of
'news', then loop through the elements looking for the right one. Once
you find it, set it to selected. Something like:
var opts = document.form1. table_name.opti ons;
for (var i=0, len=opts.length ; i<len; ++i){
if ('news' == opts[i].value){
opts[i].selected = true;
return;
}
}
// Just in case none match?
opts[0].selected = true;
If you want to match the text content, then use:

...
if ('news' == opt[i].text){
...

[...]

--
Rob
Oct 25 '05 #2
VK

Ross wrote:
i use this but select the index by name??

document.form1. table_name.sele ctedIndex= 2;
what i want

document.form1. table_name.sele ctedIndex= "news";


....
<option selected value="news">Re cent News</option>
....

1. document.form1. table_name[form1.table_nam e.selectedIndex].text='Hot
News';

(Changes "Recent News" to "Hot News")

2.
document.form1. table_name[form1.table_nam e.selectedIndex].value='hot_new s';

(Changes "news" to "hot_news")

Oct 25 '05 #3
VK
Seems I did not get your problem right.

Oct 25 '05 #4
VK wrote on 25 okt 2005 in comp.lang.javas cript:
Seems I did not get your problem right.


But I have no problem.

[please always quote on usenet, this is not email]

--
Evertjan.
The Netherlands.
(Replace all crosses with dots in my emailaddress)

Oct 25 '05 #5

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