static modifier

[sankarasubbu100]

public class Test {

private static int a;

public static void main (String [] args)
{
modify(a);
System.out.println(a);
}

public static void modify(int a) {
a++;
}

}

Please tell me why this code prints 0 instead of 1?

Thanks in advance...

[Laharl]

It does that because primitives (ints, floats, doubles, etc) are passed by value, which means that a copy of the variable with the same value is actually passed to the function. This local copy is destroyed after the function exits.

[JosAH]

It does that because primitives (ints, floats, doubles, etc) are passed by value, which means that a copy of the variable with the same value is actually passed to the function. This local copy is destroyed after the function exits.

ps. also *non-primitives* are passed by value; it's the only parameter passing
mechanism Java knows of. Those non-primitives are references which is just a
pooped up term for pointers.

kind regards,

Jos

[BigDaddyLH]

http://java.sun.com/docs/books/tutor...arguments.html