Number Averager

[Kid Programmer]

Hello guys. I was trying to write a number averaging program that would continue averaging numbers until the user enters text. Here is my source:

/* Number Avergaer
Written by Kid Programmer
Coded in Java */
 
import java.util.Scanner;    //import a scanner
 
class NumberAverager {        //create a class
    public static void main(String[] args) {    //define the main function
        int average = 0;
        System.out.println("This program will average numbers.");
        System.out.println("To stop averaging numbers type in text.");
        Scanner scan = new Scanner(System.in);  
        while ( scan.hasNextInt() ){
            int  number = scan.nextint("Please enter a number: ");
             int total_average = (average + number) / 3;
            System.out.println("The average is: " + total_average);
        }
    }
}
 

I get the following error:

NumberAverager.java:14: cannot find symbol
symbol : method nextint(java.lang.String)
location: class java.util.Scanner
int number = scan.nextint("Please enter a number: ");
^
1 error

What should I do?

[r035198x]

Java is case sensitive. nextint != nextInt

[sukatoa]

also nextInt() method with a parameter String have never been exists....

maybe int....

regards,
sukatoa

[Kid Programmer]

I fixed the problem. But I have another. There apparently is a problem with my math. Please fix it. Here is my source:

 
/* Number Avergaer
Written by Kid Programmer
Coded in Java */
 
import java.util.Scanner;    //import a scanner
 
class NumberAverager {        //create a class
    public static void main(String[] args) {    //define the main function
        int average = 0;
        System.out.println("This program will average numbers.");    //explain the program
        System.out.println("To stop averaging numbers type in text.");
        Scanner scan = new Scanner( System.in );    //create a scanner
        while ( scan.hasNextInt() ){    
            int  number = scan.nextInt();        //prompt the user for a number
            int average2 = (average + number);    //calculate part of the average
            if ( scan.hasNextInt() == false ) {    
                int total_average = average2 / 3;    //calculate the average
                System.out.println("The average is: " + total_average);        //print out the average
            }
        }
    }
}
 

I type in the numbers 1, 3, and 5 and it says the average is 1.

[r035198x]

1.) Don't use int if you need to do divisions. What if the result has a decimal part?
2.) Write down your pseudo-code algorithm for solving this problem first.

[JosAH]

The title of this thread sounded promising: a number averager; I would've expected
something like this:

NumberAverager na= new NumberAverager();
na.add(<some_number>): // do this several times
System.out.println("total: "+na.getTotal());
System.out.println("average: "+na.getAverage());
System.out.println("n: "+na.getN());
 

... but alas, a same old rigid fortranesque implementation was shown again.
I knew it for years: those Basic programmers are all lost for the posterity.

kind regards,

Jos

[Kid Programmer]

Well I tried fixing my problem and I got this error:

NumberAverager.java:21: cannot find symbol
symbol : variable number_sum
location: class NumberAverager
int total_average = number_sum / divide_by; //calculate the average
^
1 error


This is my new source:

/* Number Avergaer
Written by Kid Programmer
Coded in Java */
 
import java.util.Scanner;    //import a scanner
 
class NumberAverager {        //create a class
    public static void main(String[] args) {    //define the main function
        int average = 0;
        int divide_by = 0;
        System.out.println("This program will average numbers.");    //explain the program
        System.out.println("To stop averaging numbers type in text.");
        Scanner scan = new Scanner( System.in );    //create a scanner
        while ( scan.hasNextInt() ){            //ask the user to enter numbers until they enter text
            int number = scan.nextInt();        //prompt the user for a number
            divide_by ++;                //increase the number to divide the sum by
            while ( scan.hasNextInt() == true )  {       //while the user is still entering numbers 
                double number_sum = number + 0;
            }
            if ( scan.hasNextInt() == false ) {    //if the user entered text
                    int total_average = number_sum / divide_by;     //calculate the average
                System.out.println("The average is: " + total_average);        //print out the average
            }
        }
    }
}
 

How can I fix this?

Sincerely,
Kid Programmer

[Laharl]

 
            while ( scan.hasNextInt() == true )  {
                double number_sum = number + 0;
            }
            if ( scan.hasNextInt() == false ) {
                    int total_average = number_sum / divide_by;     
 

How can I fix this?

number_sum does not exist outside of the pair of curly braces in which it is first declared. The same is true for any other primitive (int, double, boolean, char, float, byte). Also, in your current code, if the declaration for number_sum were moved appropriately, number_sum would still always equal number.

[Kid Programmer]

But I don't want number sum to always equal number. I need it to be the sum of all the numbers entered.

[sukatoa]

But I don't want number sum to always equal number. I need it to be the sum of all the numbers entered.

eg:

var = 0;
     while( allowable ){
          var += input from user;
     }
     showAverage( var / how many times the user inputted );

regards,
sukatoa