Throw new Exception()

[gaya3]

Hi,
In the following example i'm throwing new exception from "try" block.But i havent seen the thrown exception anywhere while running the program.Eventhough there is "Finally" block ,the exception should be thrown and "finally" block should be executed.Here it was not so,because the exception is not thrown.can anyone please help me. please correct me if i'm wrong.

 
public class Test3{
    public static void main(String args[]){
        System.out.println(method());
    }
    public static int method(){
        try{
            throw new Exception();
        }
        catch(Exception e){
            throw new Exception();
        }
        finally{
            return 3;
        }
    }
}
 
 
 
 

-Thanks & Regards,
Hamsa

[Nepomuk]

Hi,
In the following example i'm throwing new exception from "try" block.But i havent seen the thrown exception anywhere while running the program.Eventhough there is "Finally" block ,the exception should be thrown and "finally" block should be executed.Here it was not so,because the exception is not thrown.can anyone please help me. please correct me if i'm wrong.

 
public class Test3{
    public static void main(String args[]){
        System.out.println(method());
    }
    public static int method(){
        try{
            throw new Exception();
        }
        catch(Exception e){
            throw new Exception();
        }
        finally{
            return 3;
        }
    }
}
 
 

-Thanks & Regards,
Hamsa

There's something strange about your catch block there... So tell me, what exactly happenes when a Exception is thrown?
Greetings,
Nepomuk

[talonx]

Hi,
In the following example i'm throwing new exception from "try" block.But i havent seen the thrown exception anywhere while running the program.Eventhough there is "Finally" block ,the exception should be thrown and "finally" block should be executed.Here it was not so,because the exception is not thrown.can anyone please help me. please correct me if i'm wrong.

 
public class Test3{
    public static void main(String args[]){
        System.out.println(method());
    }
    public static int method(){
        try{
            throw new Exception();
        }
        catch(Exception e){
            throw new Exception();
        }
        finally{
            return 3;
        }
    }
}
 
 
 
 

-Thanks & Regards,
Hamsa

You have committed a very common mistake that beginners do - returning from a finally block. Since its the last thing to be executed before it returns from the method, the exception thrown , or anything else returned, is lost.

[JosAH]

I can't help it but that catch block reminds me of a short stop in a baseball game:
catch the ball and throw it away as fast as possible again.

kind regards,

Jos ;-)

[Nepomuk]

I can't help it but that catch block reminds me of a short stop in a baseball game:
catch the ball and throw it away as fast as possible again.

kind regards,

Jos ;-)

Actually, it's like catching a ball and throwing a different ball away as fast as possible... ^^

Greetings,
Nepomuk

[JosAH]

Actually, it's like catching a ball and throwing a different ball away as fast as possible... ^^

Greetings,
Nepomuk

Yep, but in this particular example a 'finally block' comes in and returns 3
before the other party can catch my new ball.

kind regards,

Jos