Powers of two

[Doegon]

hey guys thanks for the vowel help it worked
i got one other question here.
here is the method/function signature
public int powerOfTwo(int number)

the function should return a number such that number - x is a power of two if number is already a power of two it should return 0.

[JosAH]

here is the method/function signature
public int powerOfTwo(int number)

the function should return a number such that number - x is a power of two if number is already a power of two it should return 0.

I don't understand the question: what is 'x' and is that dash '-' a minus sign?
If it is then the last phrase is redundant. Sorry for being stupid.

kind regards,

Jos

[BigDaddyLH]

The experts on this site are more than happy to help you with your problems but they cannot do your assignment/program for you. Attempt the assignment/program yourself first and post questions regarding any difficulties you have or about a particular function of the code that you don't know how to achieve.

Please read the Posting Guidelines and particularly the Coursework Posting Guidelines.

Then when you are ready post a new question in this thread.

MODERATOR

[Doegon]

public int powerOfTwo(int number)
{
int base = 2;
for(int i=0;i< Math.pow(base,Integer.MAX_VALUE);i++)
{
int powerOf2 = Math.pow(base,i);
}
}

my apologies for breaking the rules,it won't happen again.as you can see i did attempt but i can only come up with a function which i'm not sure it will give me the powers of two.

I understand x is an arbitrary number which if subtracted from the given number in parameters and one subtracted it should result in a power of two.yes that's a minus sign.

i hope this clears the question cause I'm still struggling with it

[JosAH]

Ah, I think I understand your question now, you want a function f(n) such that
x= f(n) where n-x is a power of two. Lets ignore n == 0 for now. Right?

If so, note that every number n can be written as 1xxx...xxx where xxx...xxx
are zero or more random digits. Let x = xxx...xxx then n-x is a power of two
and x is minimal.

Also note that 2^m == 1 << m.

kind regards,

Jos

[BigDaddyLH]

public int powerOfTwo(int number)
{
int base = 2;
for(int i=0;i< Math.pow(base,Integer.MAX_VALUE);i++)
{
int powerOf2 = Math.pow(base,i);
}
}

You should check with your instructor, but I think using Math.pow defeats the purpose of this exercise. I suspect you're supposed to do the math yourself.