Byte to 0 and 1 String

[Winterrage]

Greetings,

Now that i've solver my problem writting a string made of 0 and 1 to a byte. I need to do the reverse process.

I use:
Integer.toBinaryString((int)readedBytes.get(i))

It returns some odd data like:
11111111111111111111111111011011

It should be returning 8 character ? maybe I am wrong..

Anyway, is there any known way to convert a Byte into a string containing a bunch 0 and 1.

Thanks again!

[Nepomuk]

Greetings,

Now that i've solver my problem writting a string made of 0 and 1 to a byte. I need to do the reverse process.

I use:
Integer.toBinaryString((int)readedBytes.get(i))

It returns some odd data like:
11111111111111111111111111011011

It should be returning 8 character ? maybe I am wrong..

Anyway, is there any known way to convert a Byte into a string containing a bunch 0 and 1.

Thanks again!

Sure there are known ways - one (probably the wanted way) would be to do manually. You know, where the 1s and 0s come from? Say you have the Byte 9. How do you get the Binary representation (if you want 8 characters: 00001001) from that?

It's no different from what you would do manually - you just have tell your computer how to do it.

Greetings,
Nepomuk

PS.: System.out.println(Integer.toBinaryString(9)); will only give you 1001 as 0s at the front are ignored.

[JosAH]

Greetings,

Now that i've solver my problem writting a string made of 0 and 1 to a byte. I need to do the reverse process.

I use:
Integer.toBinaryString((int)readedBytes.get(i))

It returns some odd data like:
11111111111111111111111111011011

It should be returning 8 character ? maybe I am wrong..

Anyway, is there any known way to convert a Byte into a string containing a bunch 0 and 1.

Thanks again!

Bytes, shorts, ints and longs are all signed; e.g. -1 is represented as a byte as
11111111; as 1111111111111111 as a short etc. This is the 'sign extension'
mechanism. Simply take the last eight characters from the String representation
and you're in business. Or alternatively chop off all those 'generated' bits by using
this:

byte b= -1;
String rep= Integer.toBinaryString(b&0xff);
 

kind regards,

Jos

[Winterrage]

Thanks everyone for the reply :)