how to convert String to int

[deepthisoft]

hai,

I want to convert String to int.My coding is like this,

rs=stmt.executeQuery("select a from mailtable");
    rs.absolute(-1);
 
    String id=rs.getString("a");
    System.out.println(id);
 
    id= id.substring(3,(id.length()));
    System.out.println("value of id is "+ id);
 

at last this id having an numeric value ,I want to convert this to int. After this i want to add 1 to that int value.How to do this please help me.

Integer.parseInt(id);
 

This is not working. It gives NumberFormatException. Please anyone can help me.

This is very urgent for me.

[Nepomuk]

hai,

I want to convert String to int.My coding is like this,

rs=stmt.executeQuery("select a from mailtable");
    rs.absolute(-1);
 
    String id=rs.getString("a");
    System.out.println(id);
 
    id= id.substring(3,(id.length()));
    System.out.println("value of id is "+ id);
 

at last this id having an numeric value ,I want to convert this to int. After this i want to add 1 to that int value.How to do this please help me.

Integer.parseInt(id);
 

This is not working. It gives NumberFormatException. Please anyone can help me.

This is very urgent for me.

If you want the ASCII value:

System.out.println((int) id.charAt(0));
 

parseInt would give you a 1 if used with the String "1".

[dmjpro]

If you want the ASCII value:

System.out.println((int) id.charAt(0));
 

parseInt would give you a 1 if used with the String "1".

Look He is not Looking for ASCII Value.
He wants to convert into Number.

Kind regards,
Dmjpro.

[Nepomuk]

Look He is not Looking for ASCII Value.
He wants to convert into Number.

In that case, what output does

System.out.println(id);
 

create?

[dmjpro]

id= id.substring(3,(id.length()));

Are you sure that the id is equivalent to Number.
Look The NumberFormatException thrown when the Input String is not Equivalent to a number.
One more thing If you want to cut a String from a Starting Index up to Last then it's enough with id.substring(3).
Anyway, try to check that the return String whether contains any Non-Digit.
If it is then this Exception must be thrown.
Ok, Best of Luck with your try.

Kind regards,
Dmjpro.

[deepthisoft]

Are you sure that the id is equivalent to Number.
Look The NumberFormatException thrown when the Input String is not Equivalent to a number.
One more thing If you want to cut a String from a Starting Index up to Last then it's enough with id.substring(3).
Anyway, try to check that the return String whether contains any Non-Digit.
If it is then this Exception must be thrown.
Ok, Best of Luck with your try.

Kind regards,
Dmjpro.

Thanks for your reply.

I want to convert into integer. And then I sure it contains the value number.It is getting from the database.After three posisions it is only have numeric values only.And Also I checked that value using print statement it prints number.

After converted into int ,I want to add 1 to that. There is any other solution for this.

[dmjpro]

Thanks for your reply.

I want to convert into integer. And then I sure it contains the value number.It is getting from the database.After three posisions it is only have numeric values only.And Also I checked that value using print statement it prints number.

After converted into int ,I want to add 1 to that. There is any other solution for this.

Could you send me Stack Message you got in your Console.
I mean the total Exception Message.
Could you sen me please?

Kind regards,
Dmjpro.

[r035198x]

hai,

I want to convert String to int.My coding is like this,

rs=stmt.executeQuery("select a from mailtable");
    rs.absolute(-1);
 
    String id=rs.getString("a");
    System.out.println(id);
 
    id= id.substring(3,(id.length()));
    System.out.println("value of id is "+ id);
 

at last this id having an numeric value ,I want to convert this to int. After this i want to add 1 to that int value.How to do this please help me.

Integer.parseInt(id);
 

This is not working. It gives NumberFormatException. Please anyone can help me.

This is very urgent for me.

Not all Strings can be converted to integers. The string you're trying to convert to a number is not a number. That's why you got the exception.

[deepthisoft]

Not all Strings can be converted to integers. The string you're trying to convert to a number is not a number. That's why you got the exception.

String id="EAM9";
id= id.substring(3,(id.length()));
System.out.println(id);// it will print 9.
//after this i want to convert id into integer.
 

[dmjpro]

String id="EAM9";
id= id.substring(3,(id.length()));
System.out.println(id);// it will print 9.
//after this i want to convert id into integer.
 

I tested this Code.
And it works fine.

String id="EAM9";
id= id.substring(3,(id.length()));
System.out.println("Dmjpro: " + id);
Sstem.out.println("Debasis Jana: " + Integer.parseInt(id));
 

Kind regards,
Dmjpro.

[JosAH]

String id="EAM9";
id= id.substring(3,(id.length()));
System.out.println(id);// it will print 9.
//after this i want to convert id into integer.
 

Can you print out the *length* of that id String as well? I suspect some trailing
spaces or non-printing character there.

The example as it is runs fine for me.

kind regards,

Jos

[dmjpro]

Can you print out the *length* of that id String as well? I suspect some trailing
spaces or non-printing character there.

The example as it is runs fine for me.

kind regards,

Jos

yeah Jos you are right.
There may be some leading or trailing spaces or non-printing Chanracter.

Kind regards,
Dmjpro.

[deepthisoft]

It is working fine.Thank you very much for all your responses.

[JosAH]

It is working fine.Thank you very much for all your responses.

So you didn't change anything and all of a sudden it works fine? I hope you don't
mind if I don't believe that; care to elaborate on what you changed? It may come
in handy for others who are struggling with the same problem and try to google
for it; google might point them to this thread.

kind regards,

Jos