catching exceptions

[cazconv2007]

hi i need to catch and try exceptions , one for int and one for an array out of bounds i dont undertand how my code is'nt working for array out of bounds heres my code


import java.util.* ;

public class ExceptionHomework
{
Scanner scan ;
int data;
int slot;
int[] value;

/**
* Constructor for objects of class
* ExceptionHomework
*/
public ExceptionHomework()
{
scan = new Scanner( System.in );
data=0;
slot=0 ;
value = new int[10];
}



/**
* This is the method you must change by adding
* try-catch blocks
*
*/
public void sampleMethod() throws ArrayIndexOutOfBoundsException
{
System.out.print("Enter the data: ");
data = scan.nextInt();
System.out.print("Enter the array index: ");
slot = scan.nextInt();
value[slot] = data;
try{
for(slot =0;slot <10;slot++){
value[slot] = slot;
}
System.out.println(value);
}
catch(ArrayIndexOutOfBoundsException e){
//printed just to inform that we have entered the catch block
System.out.println("Oops, we went to far, better go back to 0!");
}
finally{
System.out.println(value);
//method call to continue program
}

}
}

heres my driver

public class ExceptionHomeworkDriver
{
public static void main ( String [] args)
{
ExceptionHomework exHmwk = new ExceptionHomework();
exHmwk.sampleMethod();
System.out.println("Good By");
}
}

[sandyw]

hi i need to catch and try exceptions , one for int and one for an array out of bounds i dont undertand how my code is'nt working for array out of bounds heres my code


import java.util.* ;

public class ExceptionHomework
{
Scanner scan ;
int data;
int slot;
int[] value;

/**
* Constructor for objects of class
* ExceptionHomework
*/
public ExceptionHomework()
{
scan = new Scanner( System.in );
data=0;
slot=0 ;
value = new int[10];
}



/**
* This is the method you must change by adding
* try-catch blocks
*
*/
public void sampleMethod() throws ArrayIndexOutOfBoundsException
{
System.out.print("Enter the data: ");
data = scan.nextInt();
System.out.print("Enter the array index: ");
slot = scan.nextInt();
value[slot] = data;
try{
for(slot =0;slot <10;slot++){
value[slot] = slot;
}
System.out.println(value);
}
catch(ArrayIndexOutOfBoundsException e){
//printed just to inform that we have entered the catch block
System.out.println("Oops, we went to far, better go back to 0!");
}
finally{
System.out.println(value);
//method call to continue program
}

}
}

heres my driver

public class ExceptionHomeworkDriver
{
public static void main ( String [] args)
{
ExceptionHomework exHmwk = new ExceptionHomework();
exHmwk.sampleMethod();
System.out.println("Good By");
}
}

I'm learn this myself...
Question what does the
1.

catch(ArrayIndexOutOfBoundsException e){

e stand for I think you want exception instead of e.
2. not sure you might need a return
finally{
System.out.println(value);
//method call to continue program
}
return //what int you are looking for
}

sandyw

[cazconv2007]

changed some of the code but now it doesnt like my driver which i dont know why, error says unreported exception java.lang.exception must be caught


import java.util.* ;

public class ExceptionHomework
{
Scanner scan ;
int data;
int slot;
int[] value;

/**
* Constructor for objects of class
* ExceptionHomework
*/
public ExceptionHomework()
{
scan = new Scanner( System.in );
data=0;
slot=0 ;
value = new int[10];
}



/**
* This is the method you must change by adding
* try-catch blocks
*
*/
public void sampleMethod() throws Exception

{
try{
System.out.print("Enter the data: ");
data = scan.nextInt();
System.out.print("Enter the array index: ");
slot = scan.nextInt();
value[slot] = data;

}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Error: Array Index Out of Bounds");

}

catch (InputMismatchException e){
System.out.println ("Execption enter a number:" + e );
}

finally {
System.out.println(value);


}
}


}

my driver

public class ExceptionHomeworkDriver
{
public static void main ( String [] args)
{
ExceptionHomework exHmwk = new ExceptionHomework();
exHmwk.sampleMethod();
System.out.println("Good By");
}
}

[r035198x]

changed some of the code but now it doesnt like my driver which i dont know why, error says unreported exception java.lang.exception must be caught


import java.util.* ;

public class ExceptionHomework
{
Scanner scan ;
int data;
int slot;
int[] value;

/**
* Constructor for objects of class
* ExceptionHomework
*/
public ExceptionHomework()
{
scan = new Scanner( System.in );
data=0;
slot=0 ;
value = new int[10];
}



/**
* This is the method you must change by adding
* try-catch blocks
*
*/
public void sampleMethod() throws Exception

{
try{
System.out.print("Enter the data: ");
data = scan.nextInt();
System.out.print("Enter the array index: ");
slot = scan.nextInt();
value[slot] = data;

}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Error: Array Index Out of Bounds");

}

catch (InputMismatchException e){
System.out.println ("Execption enter a number:" + e );
}

finally {
System.out.println(value);


}
}


}

my driver

public class ExceptionHomeworkDriver
{
public static void main ( String [] args)
{
ExceptionHomework exHmwk = new ExceptionHomework();
exHmwk.sampleMethod();
System.out.println("Good By");
}
}

1.)Please use code tags when posting code.
2.) Read the error message. It is telling what you need to do. You need to add a catch clause that catches Exception.

[cazconv2007]

sorry i dont know what code tags are

i added


catch (Throwable e) {
System.out.println ("exception");
}

and tried


catch (Exception e) {
System.out.println ("exception");
}

is this what you meant because it didnt work thank for replying tho

[cazconv2007]

thanks everyone for your help but finally done it