the problem again

[analoveu]

I have a problem with printing the spaces at the begining of each line in the following shape

1
121
12321
1234321
12321
121
1

but the code i developed print it like that
1
121
12321
1234321
12321
121
1

and this is the code i developed

import java.util.Scanner;
public class Main {
 
    public static void main(String[] args) {
 
      final int N=1;
 
      System.out.println( "Enter the centered number " ); 
      Scanner input =new Scanner(System.in);
      int centeredNumber;
      centeredNumber=input.nextInt();
          for(int x=0;x<centeredNumber;x++)
           {
             String p="";
             for(int k=1 ;k<N+x;k++)
                 p+=k; 
 
             StringBuffer str = new StringBuffer(p);
             System.out.print(str);
             System.out.print(N+x);
             str.reverse();
             System.out.println(str);
 
              if(x==centeredNumber-1)
              {
                  for(int xx=x-1;xx>=0;xx--)
           {
             String pp="";
             for(int k=1  ;k<N+xx;k++)
                 pp+=k; 
 
              StringBuffer str1 = new StringBuffer(pp);
              System.out.print(str1);
              System.out.print(N+xx);
              str1.reverse();
              System.out.println(str1);
 
                  }
              }
 
 
         }
    }
 
}

I wanna know how i print the spaces at the begining of each line
here you will enter the wanted input number ,variable centeredNumber, as 4
to print the shape i put it

[Ganon11]

Suppose the user enters 1. Then you will need to print 0 spaces.

Suppose the user enters 2. Then you will need to print 1 space on the first line, 0 on the 2nd line, and 1 on the last line.

Suppose the user enters 3. Then you will need to print 2 spaces on the first line, 1 space on the second line, 0 spaces on the third line, 1 space on the fourth line, and 2 spaces on the fifth line.

Do you see the pattern emerging?

Can you generalize this? In other words, fill in the blanks:

Suppose the user enters ____. Then you will need to print ____ spaces on the first line, ____ spaces on the second line....0 spaces on the middle line...____ spaces on the last line.

[analoveu]

Suppose the user enters 1. Then you will need to print 0 spaces.

Suppose the user enters 2. Then you will need to print 1 space on the first line, 0 on the 2nd line, and 1 on the last line.

Suppose the user enters 3. Then you will need to print 2 spaces on the first line, 1 space on the second line, 0 spaces on the third line, 1 space on the fourth line, and 2 spaces on the fifth line.

Do you see the pattern emerging?

Can you generalize this? In other words, fill in the blanks:

Suppose the user enters ____. Then you will need to print ____ spaces on the first line, ____ spaces on the second line....0 spaces on the middle line...____ spaces on the last line.

ok i know that but my problem is how write code to do that
how to print 3 spaces using the code
how to tell it print 2 or 3 spaces , printing spacing like this" " ," " not suitable with my code
is not there another way to do this?iside the firs for

 for(int x=0;x<centeredNumber;x++)

in the first loop, i want print spaces equal to centeredNumber-1
in the second loop, i wanna print spaces equal to centeredNumber-2
....and so on

[abctech]

Hi,
I used the foll logic for the same program -

For the upper triangular-part of this diamond shape I'd written the below code:-
Note:- 't' is the number of lines or say the centered number

class ABC
{
  public static void main(String args[])
  {
    int i,j,t;
   //ask the user to input the centered number and store it in say 't' 
 
    for (j=1;j<=t;j++) //this 'nested-for' is for creating the upper-triangular-portion
    {            
     for (i=1;i<=t-j;i++)
     {
       System.out.print(" ");
     }
     for (i=1;i<=j;i++)
     {
       System.out.print(i);                
     }
     for (i=j-1;i>=1;i--)
     {
       System.out.print(i);
     }
     System.out.println();
    }
 
    for()//this 'nested-for' is for creating the lower-portion
    {
    --Here--
    }
  }
}

so if the user inputs 4 means t=4 then the above code will generate the o/p as below-

1
121
12321
1234321

Now using a similar logic try to develop the second nested-for(--Here--) to print the lower-inverted triangular portion,i.e

12321
121
1

It will be quite easy if you can understand the first nested-for.

[analoveu]

Hi,
I developed this code to solve this problem
I think this is shorter

import java.util.Scanner;   //import class Scanner for the input 
public class DiamondNumbers {
    public static void main(String[] args) {
 
      final int N=1;
 
      System.out.println( "Enter your centered number Starting from number 1" ); 
      Scanner input =new Scanner(System.in);
      int centeredNumber;
      centeredNumber=input.nextInt();
          for(int x=0;x<centeredNumber;x++)  //control the count of the lines up to the centered line
            {
               for(int s=1;s<centeredNumber-x;s++)   //print the spaces at the beginning of each line
                   System.out.print(" ");
 
                String p="";
                for(int k=1 ;k<N+x;k++)        // print each line of the upper triangular portion
                    p+=k; 
 
                 StringBuffer str = new StringBuffer(p);
                 System.out.print(str);     //print the string of the numbers before the middle number
                 System.out.print(N+x);    //print the middle number of each line
                 str.reverse();          
                 System.out.println(str);   //print the string of the numbers after the middle number
 
 
                if(x==centeredNumber-1)       //Check if you reached to the centered number or the centered line
                  {
                    for(int xx=x-1;xx>=0;xx--)  //counter for the lines under the centered line 
                      {
 
                        for(int s=1;s<centeredNumber-xx;s++)    //print the spaces at the beginning of each line
                           System.out.print(" ");
 
                         String pp="";
                         for(int k=1  ;k<N+xx;k++)     // print each line of the lower-inverted triangular portion
                             pp+=k; 
 
                          StringBuffer str1 = new StringBuffer(pp);
                          System.out.print(str1);     //print the string of the numbers before the middle number
                          System.out.print(N+xx);     //print the middle number of each line
                          str1.reverse();
                          System.out.println(str1);   //print the string of the numbers after the middle number
 
                        }
                     }
 
               }
  } 
}

[abctech]

Hi,
I developed this code to solve this problem
I think this is shorter

import java.util.Scanner;   //import class Scanner for the input 
public class DiamondNumbers {
    public static void main(String[] args) {
 
      final int N=1;
 
      System.out.println( "Enter your centered number Starting from number 1" ); 
      Scanner input =new Scanner(System.in);
      int centeredNumber;
      centeredNumber=input.nextInt();
          for(int x=0;x<centeredNumber;x++)  //control the count of the lines up to the centered line
            {
               for(int s=1;s<centeredNumber-x;s++)   //print the spaces at the beginning of each line
                   System.out.print(" ");
 
                String p="";
                for(int k=1 ;k<N+x;k++)        // print each line of the upper triangular portion
                    p+=k; 
 
                 StringBuffer str = new StringBuffer(p);
                 System.out.print(str);     //print the string of the numbers before the middle number
                 System.out.print(N+x);    //print the middle number of each line
                 str.reverse();          
                 System.out.println(str);   //print the string of the numbers after the middle number
 
 
                if(x==centeredNumber-1)       //Check if you reached to the centered number or the centered line
                  {
                    for(int xx=x-1;xx>=0;xx--)  //counter for the lines under the centered line 
                      {
 
                        for(int s=1;s<centeredNumber-xx;s++)    //print the spaces at the beginning of each line
                           System.out.print(" ");
 
                         String pp="";
                         for(int k=1  ;k<N+xx;k++)     // print each line of the lower-inverted triangular portion
                             pp+=k; 
 
                          StringBuffer str1 = new StringBuffer(pp);
                          System.out.print(str1);     //print the string of the numbers before the middle number
                          System.out.print(N+xx);     //print the middle number of each line
                          str1.reverse();
                          System.out.println(str1);   //print the string of the numbers after the middle number
 
                        }
                     }
 
               }
  } 
}

Whatever works,glad that your program is done!
Cheers