count number of words in a string

[kishore314]

Hi,
Just a small excerise for me.
A program that counts number of words in a string.

The program which i have written now is -

import java.io.*;
class countword 
{
    private static BufferedReader stdin = new BufferedReader(new InputStreamReader( System.in ));
 
    public static void main(String arg[]) throws IOException  {
    System.out.println("Enter a string: ");
    String input = stdin.readLine();
 
    String[] arr = input.split(" ");
    int length = arr.length;
    System.out.println ("Lenght of string: "+input+" is:"+length);
   }
}
 

But this counts even extra blank spaces. Like this string "I am new to JAVA",
or " I am new to java" should count only as 5 words, but the result shows more than that.

Any suggestions to change the logic?


Cheers,

Kishore

[r035198x]

Hi,
Just a small excerise for me.
A program that counts number of words in a string.

The program which i have written now is -

import java.io.*;
class countword
{
private static BufferedReader stdin = new BufferedReader(new InputStreamReader( System.in ));

public static void main(String arg[]) throws IOException {
System.out.println("Enter a string: ");
String input = stdin.readLine();

String[] arr = input.split(" ");
int length = arr.length;
System.out.println ("Lenght of string: "+input+" is:"+length);
}
}


But this counts even extra blank spaces. Like this string "I am new to JAVA",
or " I am new to java" should count only as 5 words, but the result shows more than that.

Any suggestions to change the logic?


Cheers,

Kishore

From

 String[] arr = input.split(" ");

then you do

 int count = 0; 
for(int i = 0; i <arr.length;i++) {
if(arr[i].equals(" ")) {
}
else {
    count++;
}
}
 

and

 int length = count;

[kishore314]

hey,
that was a very quick reply!! Really unexpected and great ;-)

it works fine.

Thanks a lot!

Cheers,
Kishore

[r035198x]

hey,
that was a very quick reply!! Really unexpected and great ;-)

it works fine.

Thanks a lot!

Cheers,
Kishore

Anytime Kishore. Just remember to use code tags next time you post your code either in helping others or in asking more questions

[kishore314]

Anytime Kishore. Just remember to use code tags next time you post your code either in helping others or in asking more questions

I am a newbie to this forum, but i get what u meant :-)

hey, is there any other method WITHOUT USING SPLIT() for this program?

[r035198x]

I am a newbie to this forum, but i get what u meant :-)

hey, is there any other method WITHOUT USING SPLIT() for this program?

Combination of split and a regular expression is the best approach. The tokenizer route is becoming archaic

[kishore314]

Combination of split and a regular expression is the best approach. The tokenizer route is becoming archaic

No clue how to go about it...HELP!!!

[r035198x]

No clue how to go about it...HELP!!!

You'd need to go through a regular expression tutorial first. One is found here

[Glenn Setliff]

Looks like the solution is instead to use input.split("\\s+") to get the count instead of input.split(" ") and then just output the length.

[Parth Gallen]

"one&two#three|four" will return as 4 words.
"I'm here" 3 words and so on.
Just didn't think " " is enough to separate words.

public static int countWords(String s) {
    int counter = 0;
    boolean word = false;
    int endOfLine = s.length()-1;
 
    for (int i = 0; i < s.length(); i++) {
      //if the char is letter, word = true.
      if (Character.isLetter(s.charAt(i)) == true && i != endOfLine) {
        word = true;
      //if char isnt letter and there have been letters before (word == true), counter goes up.
      } else if (Character.isLetter(s.charAt(i)) == false && word == true) {
        counter++;
        word = false;
      //last word of String, if it doesnt end with nonLetter it wouldnt count without this.
      } else if (Character.isLetter(s.charAt(i)) && i == endOfLine) {
        counter++;
      }
    }
    return counter;
  }

[eeree]

Try splitting with Regular Expressions instead of using " " as delimiter:

String[] arr = input.split("\\s+");
     int length = arr.length;

That code will split String on any space character (space \n \r or \t) (if there is more characters in a row it will split only once).

[123jyotsna]

Could use the following code:

import java.io.*;

public class Countstringwords {

private static BufferedReader stdin = new BufferedReader(new InputStreamReader( System.in ));

public static void main(String arg[]) throws IOException {
System.out.println("Enter a string: ");
String input = stdin.readLine();
int i,l = 0;
String[] arr = input.split(" ");
int length = arr.length;
for(i=0;i<length;i++){
System.out.println(arr[i]);
if(!"".equals(arr[i])){l++;}

}
System.out.println ("Lenght of string: "+input+" is:"+l);
} }

[Rica Vida]

can u explain that.,please.,i need explanation.,tnx