Thanks Oliver!
I found that Math.Round(float) -> int, thus I can do as follows:
float f = 1.234;
f *= 100;
f = (float)Math.round(f)/100;
.... and now f==1.23
Terje
"Oliver Wong" <ow***@castortech.com> skrev i melding
news:Wp2ff.200172$ir4.172405@edtnps90...
"Terje Barman" <terje_nospam_@_nospam_barman-hanssen.no> wrote in message
news:7N********************@telenor.com... Hi!
I have sumarized float values and I'd like to round the sum to a certain
precision. Say I have 1.234 and want it rounded to 1.23. Which method can
I use?
Math.round();
- Oliver