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504 error

freddieMaize
85 New Member
Hi all,

I used the below,
Expand|Select|Wrap|Line Numbers
  1. InputStream in = new URL ("http://127.0.0.1/search?q=travel") .openStream () ; 
I'm getting the below,
[HTML]java.io.IOExcep tion: Server returned HTTP response code: 504 for URL: http://127.0.0.1/search?q=travel[/HTML]

I've also set the proxies. Also, for your information, when i just chang the url to yahoo.com, its working fine.

Any inputs would help me.

Thanks,
fREDDIE

Out of the box question: I started a thread under networking. Is there a way to move it to somewhere else? May be here??
Nov 18 '08 #1
17 7892
JosAH
11,448 Recognized Expert MVP
Do you have a web server or servlet container etc. running on your local host on
your default port (80)?

kind regards,

Jos
Nov 18 '08 #2
freddieMaize
85 New Member
Do you have a web server or servlet container etc. running on your local host on
your default port (80)?
Hi JosAH, i'm actually using those in a standalone java program. So no servlets or web servers are in picture. Sorry i forgot to tell this in the first post.

fREDDIE
Nov 18 '08 #3
JosAH
11,448 Recognized Expert MVP
Hi JosAH, i'm actually using those in a standalone java program. So no servlets or web servers are in picture. Sorry i forgot to tell this in the first post.
But then it can never work because you explicitly state that you want to use the
http protocol on your local host (default port 80). There is nothing listening on
that port. If you change your url to point to the yahoo site it works because
yahoo does have such a server available.

kind regards,

Jos
Nov 18 '08 #4
freddieMaize
85 New Member
But then it can never work because you explicitly state that you want to use the
http protocol on your local host (default port 80). There is nothing listening on
that port. If you change your url to point to the yahoo site it works because
yahoo does have such a server available.
I would again apologies. Oh god why am i doing this.

The actual url that i used was something like below,

Expand|Select|Wrap|Line Numbers
  1. InputStream in = new URL ("http://Anothermachine/search?q=travel") .openStream () ;  
To make sure that i dont show up the ip of the server machine that i use (just to be on the safer side) i gave localhost. My mistake.

fREDDIE
Nov 19 '08 #5
r035198x
13,262 MVP
The same question that you were asked by Jos holds for that other machine of yours. If there is a server running there then make sure there are no security restrictions blocking access to the port you are trying to get to.
Nov 19 '08 #6
freddieMaize
85 New Member
The same question that you were asked by Jos holds for that other machine of yours. If there is a server running there then make sure there are no security restrictions blocking access to the port you are trying to get to.
Hi, But the url is accessible from my machine if i use it in the address bar. That is how we check if the server is up right? Kindly correct if i'm wrong.

I'll put it in simple terms. If a url works in my browser then obviously i should be able to use that url in my application right?

fREDDIE
Nov 19 '08 #7
r035198x
13,262 MVP
Hi, But the url is accessible from my machine if i use it in the address bar. That is how we check if the server is up right? Kindly correct if i'm wrong.

I'll put it in simple terms. If a url works in my browser then obviously i should be able to use that url in my application right?

fREDDIE
OK then. It's purely a timing out issue then. When you try from the browser, you put exactly the same url as the one in the code right?
Nov 19 '08 #8
freddieMaize
85 New Member
OK then. It's purely a timing out issue then. When you try from the browser, you put exactly the same url as the one in the code right?
Exactly the same. In fact i used ctrl+c and ctrl+v.
Nov 19 '08 #9
r035198x
13,262 MVP
Exactly the same. In fact i used ctrl+c and ctrl+v.
Just trying to eliminate another doubt with your proxy ...

Instead of openStream(), try using openConnection( aProxy).getInpu tStream();
For the aProxy part, first try Proxy.NO_PROXY. If that doesn't work then try creating a Proxy object using your proxy settings and use that instead.
Nov 19 '08 #10

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