Include a style from another class

[StarQuake]

For example:

I have two css files. One with the class foo and one with the class bar:

foo.css:
---------
..foo {
font-size : 12px;
}

bar.css:
---------
..bar {
some include function here
}

What I want is that the class bar becomes exactly the same as foo.

Thanks!

StarQuake

--
for some how-to's and rpms visit my site : http://solid.bounceme.net
for commercially supported solutions visit : http://www.robas.com

['sNiek]

StarQuake schreef:

For example:

I have two css files. One with the class foo and one with the class bar:

foo.css:
---------
.foo {
font-size : 12px;
}

bar.css:
---------
.bar {
some include function here
}

What I want is that the class bar becomes exactly the same as foo.

Thanks!

StarQuake

Just call it .foo and the styles it will overrule (or supplement) the styles in the foo.css
--
Niek

[StarQuake]

'sNiek wrote:

StarQuake schreef:

For example:

I have two css files. One with the class foo and one with the class bar:

foo.css:
---------
.foo {
font-size : 12px;
}

bar.css:
---------
.bar {
some include function here
}

What I want is that the class bar becomes exactly the same as foo.

Thanks!

StarQuake

Just call it .foo and the styles it will overrule (or supplement) the
styles in the foo.css

Yes, that would be possible but the problem is I can't change the code
that refers to both foo.css and bar.css

So I'd rather do something like this:

..bar {
include .foo
}

If there's no solution I can just copy the contents of the foo class to
the bar class but then everytime I change foo I will have to change bar too.

StarQuake
--
for some how-to's and rpms visit my site : http://solid.bounceme.net
for commercially supported solutions visit : http://www.robas.com

['sNiek]

StarQuake schreef:

'sNiek wrote:

StarQuake schreef:

For example:

I have two css files. One with the class foo and one with the class bar:

foo.css:
---------
.foo {
font-size : 12px;
}

bar.css:
---------
.bar {
some include function here
}

What I want is that the class bar becomes exactly the same as foo.

Thanks!

StarQuake

Just call it .foo and the styles it will overrule (or supplement) the
styles in the foo.css

Yes, that would be possible but the problem is I can't change the code
that refers to both foo.css and bar.css

So I'd rather do something like this:

.bar {
include .foo
}

If there's no solution I can just copy the contents of the foo class to
the bar class but then everytime I change foo I will have to change bar
too.

StarQuake

Another solution would be something like <p class="foo bar">
--
Niek

[Stan Brown]

On Tue, 20 Sep 2005 10:56:08 +0200 in
comp.infosystems.www.authoring.stylesheets, StarQuake favored us
with...

So I'd rather do something like this:

.bar {
include .foo
}

If there's no solution I can just copy the contents of the foo class to
the bar class but then everytime I change foo I will have to change bar too.

This is an FAQ; the answer is "no way in CSS, but you can always
implement some sort of text preprocessing to build your CSS file."

--
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
http://OakRoadSystems.com/
HTML 4.01 spec: http://www.w3.org/TR/html401/
validator: http://validator.w3.org/
CSS 2.1 spec: http://www.w3.org/TR/CSS21/
validator: http://jigsaw.w3.org/css-validator/
Why We Won't Help You:

http://diveintomark.org/archives/200..._wont_help_you

[Jef Driesen]

StarQuake wrote:

For example:

I have two css files. One with the class foo and one with the class bar:

foo.css:
---------
.foo {
font-size : 12px;
}

bar.css:
---------
.bar {
some include function here
}

What I want is that the class bar becomes exactly the same as foo.

If you used only one css file you could do something like this:

..foo, .bar {
// Common properties
}
..foo {
// Different properties (foo only)
}
..bar {
// Different properties (bar only)
}