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what's the next number in this sequence?

2
hi everyone!here's the problem:

1729 2492 2411

what is the number that follows?????
Jul 19 '07 #1
16 2461
rita84
2
i'll give you a hint...

one of the digits in the 4-digit number that follows is 8...

good luck!!
Jul 19 '07 #2
TRScheel
638 Expert 512MB
i'll give you a hint...

one of the digits in the 4-digit number that follows is 8...

good luck!!
Cool, down to 999 different options instead of 9999!

=P
Jul 19 '07 #3
hariharanmca
1,977 1GB
Cool, down to 999 different options instead of 9999!

=P

Can you explain, What you mean?
Aug 1 '07 #4
TRScheel
638 Expert 512MB
Can you explain, What you mean?
Well its more than that, I just didnt want to take the time to figure it out. But if he takes the possible number we have to figure out down to three digits instead of four, it drastically drops the number of possibilities
Aug 1 '07 #5
acoder
16,027 Expert Mod 8TB
Can you explain, What you mean?
We know that one of the digits is 8, so the possibilities have decreased from 9999 to 999. However, I don't think that's quite true. I can't be bothered explaining why - I'll leave that to someone else.
Aug 1 '07 #6
TRScheel
638 Expert 512MB
We know that one of the digits is 8, so the possibilities have decreased from 9999 to 999. However, I don't think that's quite true. I can't be bothered explaining why - I'll leave that to someone else.
It isnt quite true, because we dont know where the 8 is. So you could have:

8xxx
x8xx
xx8x
xxx8

So the possiblities are(?) 999 * 4 = 3996
Aug 1 '07 #7
TRScheel
638 Expert 512MB
1729 2492 2411

011011000001
100110111100
100101101011

6c1
9bc
96b

Just turning the number to binary and hex to see if anyone (or myself) can make something of it
Aug 1 '07 #8
TRScheel
638 Expert 512MB
I believe the answer is 1558

EDIT: How I got there:

011011000001 = 1729
100110111100 = 2492
100101101011 = 2411
011000010110 = 1558

If you notice, the patterns of the binary representations of these numbers go either:

11001100...
or
10101010...

So I just completed the pattern
Aug 1 '07 #9
Darryl
86
It isnt quite true, because we dont know where the 8 is. So you could have:

8xxx
x8xx
xx8x
xxx8

So the possiblities are(?) 999 * 4 = 3996
That's still wrong :-(

If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.

However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
Aug 2 '07 #10
TRScheel
638 Expert 512MB
That's still wrong :-(

If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.

However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
Somehow I knew I was way off, lol
Aug 3 '07 #11
TRScheel
638 Expert 512MB
Considering the only two posts this member made were to post the question and the hint, I wonder if we will ever know the answer
Aug 3 '07 #12
JosAH
11,448 Expert 8TB
Considering the only two posts this member made were to post the question and the hint, I wonder if we will ever know the answer
I know the first number is the Ramanujan - Hardy cab number (*) but I'm also
stuck in finding any regularity for the next numbers,

kind regards,

(*) the smallest non-trivial positive number that equals the sum of two cubes in
two different ways (1^3+12^3 == 9^3+10^3)
Aug 4 '07 #13
sitko
140 100+
i attempted to delete this post...but couldn't figure out how.
Sep 6 '07 #14
That's still wrong :-(

If we assume 8 is available for the unknown digits, we have 10 possible values for 3 digits. 10*10*10 = 1000. Then multiply by 4 = 4000.

However, if we assume 8 is not duplicated then we'd have 9*9*9=729. Multiplied by 4 = 2916
well this is not correct as well
since it is a 4 digit no.
8xxx
x8xx
xx8x
xxx8
u cant have the digit at thousandth position as 0

Now no. of possibility gets reduced to

8xxx = 10*10*10
x8xx = 9*10*10 since digit at thousandth position cant be 0
xx8x = 9*10*10
xxx8 = 9*10*10

so the no of possibilities are 3700
Sep 7 '07 #15
hariharanmca
1,977 1GB
i attempted to delete this post...but couldn't figure out how.
There you are!!! That’s why this site allow admin to do that.
Sep 7 '07 #16
sitko
140 100+
this one bugged me, so I went to google and searched for those three numbers, and the only thing that came up was rita's posts on 2 other forum sites, asking the same question. So, I fear that she was just some lurker who was hoping we'd do her homework FOR her.

:|

Although on one of the sites, someone guessed "2498" but didn't provide any reasoning on to how he came up with that number...
Sep 7 '07 #17

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