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# Probability and distribution Problem?

 P: 1 I have to formulate this in excel and was wondering if anyone could help me with the formulas. It has also determined that the number of repair claims filed each week is a random variable which can take values 1, 2, 4, 5, 6, 7, 8, 9. The probability of having 1 or 9 claims in a week is equal. The probability that there are 2, 6, 7 or 8 claims in a week is twice the probability of there being a single claim. The probability that there are 4 claims in a week is twice the probability that there are 2 claims in a week. The probability that there are 5 claims in a week is 6 times the probability that there is a single claim in a week. The dollar amount per claim fits a normal distribution with a mean claim amount of \$2000 and a standard deviation of \$400. In addition to repair claims, the company also receives claims for cars that have been “totaled” and cannot be repaired. There is a 20% chance in any week of receiving this type of claim. The claims for “totaled” cars cost has a uniform distribution, in the range \$10000 to \$35000. Not all repair claims are legitimate: 1% of the repair claims filed are rejected. Of the “totaled” claims filed, 0.5% of them are rejected. I'm not sure how to make the formulas for paragraph 1. And then I don't know how to incorporate the probability into the random uniform distribution and how to incorporate the reject variable. Any help would be greatly appreciated. Jun 21 '14 #1