How to prevent the previous result from showing

[JoeyTheGreat]

I'm 10th grade doing our project in IT.

It tasked us to convert decimal to binary and ask the user if he wants to try again or not.

I did that using the goto but when I type another decimal it shows the previous result

#include<stdio.h>
 
int n, r, i=1, b=0; 
char command;
int main(void)
 
{
start:
    printf("enter a decimal: ");
    scanf(" %i", &n);
 
    while(n>0)
 
    { 
    r=n%2;
    n=n/2;
    b=b+r*i;
    i=i*10;
 
    }
    printf("%i", b);
 
 
 char command;
    printf("\n Would you like to try again?[Y/N] \n");
 
    scanf(" %c", &command);    
 
    while(command=='Y')
    {
        goto start;
        break;
}
 
    printf("Goodbye!");
 
 
 
    return 0;  
    }

[weaknessforcats]

I didn't do a complete debug but I did notice your variable i is not initialized when you start your loop. Therefore, i has the value from the first number when the loop starts the second number. The effect is to add the binary digits of the second number behind those of the first number.

Now when you display i as a char you see the bits from the first number.

I would display either define i as a char or leave it an int and display it as an int.

BTW you ask the user for a decimal but you are expecting an int. I would ask for an integer.

[Kendots]

It's quite simple, you need b to start at 0, and i at 1 everytime.
When you restart from the goto, it keeps their current values, so you should put b=0; i=1; straight after the start :