stopping a loop

[gfanning23]

I have been struggling with this ever since my first post. I need to break this loop by way of too many integers entered.

#include <stdio.h>
int main ()
{
/* variable definition: */
int count, value, sum; double avg;
/* Initialize */
count = 0;
sum = 0; avg = 0.0;
// Loop through to input values
while (count < 5)
{
printf("Enter a positive Integer\n");
scanf("%d", &value); 
 if (value >= 0) 
 { sum = sum + value; count = count + 1; } 
 else { printf("Value must be positive\n"); }
}
// Calculate avg. Need to type cast since two integers will yield an integer
avg = (double) sum/count;
printf("average is %lf\n " , avg );
return 0;
}

I don't really understand what the count = count + 1 means either.

[Luuk]

If I may answer your last question, what the count=count + 1 means:
The value of the variable 'count' is assigned with the value of 'count + 1'
(or, in other words, count is incremented by 1)


You also may do some googling on 'programming c course'

[weaknessforcats]

There's nothing you can do to stop a loop based on data entry by the user. The reason is that while the data entry occurs, your program is not running. That is, a scanf(%d, &value) does not force the user to enter anything specific. When scanf runs all it does is interpret data already entered on sysin.

Worse, if you find that there are more than five integers in sysin, there's no way to flush the input buffer because that buffer is not yours to control. It belongs to the system. BTW: You can flush output buffers because those you created yourself and therefore are yours to control.

Editing user input is a major programming effort. scanf is just intended to get you started and not meant for any serious work. My advice while you are learning is to use friendly input at all times. If you insist on 5 integers, then be sure you enter 5 integers.