Cannot convert 'int**' to 'int*' for argument '1' to 'void shw(int*)' ?

[HRKA]

#include<stdio.h>
void disp(int *n);
void shw(int *k);
main()
{   int i;
    int arr[7]={8,2,3,4,5,6,7};
    for(i=0;i<=6;i++)
    {
        disp(&arr[i]);
    }
}
void disp(int *n)
{
    shw(&n);
}
void shw(int **k)
{
    printf("%d",**k);
}

[weaknessforcats]

The function prototype is:

void shw(int *k);

so &n is an int**.

Never mind the function definition is:

void shw(int **k)
{ etc...

because that's some other function. Unless there's an error in the prototype...

[donbock]

Function shw appears three times:

1. Line 3: function prototype.
2. Line 14: function called.
3. Line 16: function definition.

The function prototype is inconsistent with the rest; and also with how the function uses its argument on line 18.

I think the prototype is wrong.