Error] cannot convert 'float**' to 'float*' for argument '1' to 'void fill(float*, in

[nicrochaos]

#include<stdio.h>

void fill(float *av,int *max,int *i,FILE *p,int n)
{
while(!feof(p))
{
*av+=n;
if(*max<n)
*max=n;
(*i)++;
}
*av=(n)/(*i);
fclose(p);
}


the call is{
p=fopen(fn,"r");
fill(&av,&max,&i,p,n);
fclose(p);
}
the message in the description keeps popping up.I tried changing almost everything, but nothing seems to work.i'd really appreciate it if you show me your guidance,for i'm a total beginner, started a month ago!!

[donbock]

Please show us the definitions (types) for the variables being passed to fill when you call it.

[donbock]

My guess is av is defined as an array of floats. If so, then...

• function1(av[0]) passes a single float value.
• function2(av) passes a single float* value that points at the first element in the array.
• function3(&av[2]) passes a single float* value that points at the third element in the array.
• function4(&av) passes a single float** value that points to a pointer to the first element in the array.

float* is a pointer to a float variable.
float** is a pointer to a variable which in turn is a pointer to a float variable.

Click on the Articles tab and then look at the entry named Arrays Revealed for a much more complete explanation. (I can't seem to embed a link today.)

[nicrochaos]

solved it
turned out that the declaration was wrong,float *av
led to the float** issue, though i didn't know what the ** was about at first,so thanks for opening my eyes on the subject.
i really appreciate it.