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String is getting printed even after the size of array is exceeded

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
char name[5];
cout<<"Enter your name";
cin>>name;
cout<<"Your name is"<<name;
getch();
}

In the above program the size of the array of the variable name is 5. which means the variable cant store more than 5 characters.
which also means
If I give the string "LINISH"
It should only print LINIS
But while the program is running, Even if I type a 10 characters string, It is getting printed Completely..why???

Kindly be kind enough to go through the below program also:

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
char name[5];
char game[5]
cout<<"Enter your name";
cin>>name;
cout<<"Enter your favorite game";
cin>>game;
cout<<name"Loves"<<game;
getch();
}

In this program when I input a string for the variable name,It is getting printed completely, irrespective how many characters are there in the string.
But If the string (which is input to the second variable that is game )holds more than 5 characters. the input of the first variable(name) is getting disturbed..why??/

look at the below cited output to be more clear about my doubts.
OUTPUT NO:1

Enter your name:LINISHFRANCIS (Note that the input holds more than five chars)
Enter your game:GOLF(input is less than five chars)

LINISHFRANCIS loves GOLF(Two inputs are getting printed comopletely)

OUTPUT NO:
Enter your name:LINISHFRANCIS (Note that the input holds more than five chars)
Enter your game:FOOTBALL(input is more than five chars)

ALL loves FOOTBALL [Note that "ALL" is the last three letters of FOOTBALL

I am using TurboC++ for windows 7

Thanks in advance
Mar 4 '15 #1
5 1474
weaknessforcats
9,208 Expert Mod 8TB
There are no array controls in C or C++. There are no string controls either. So, a string will print until a \0 is encountered regardless of how much memory is involved. Try it sometime. Omit the \0 and print the string and see what happens.

An array is just a piece of allocated memory. You can store a 100 byte string in an array of 5 bytes. Of course, the last 95 bytes is laying outside the array memory and has just trashed something else and when your program uses those bytes it crashes with a memory corruption error.

Your experience with the string and printf is called indeterminate results. Maybe it works and maybe it doesn't.

You are the one managing memory. Not the compiler.

You also might read: http://bytes.com/topic/c/insights/77...rrays-revealed
Mar 4 '15 #2
Thank you much.....the first half of my question is answereds clearly...i really wonder if you could answer the second half too..
Mar 4 '15 #3
weaknessforcats
9,208 Expert Mod 8TB
It's like I said: Indeterminate behavior.

I compiled your code and ran it on Visual Studio 2013 and I get: LinishFrancislovesfootball followed by a runtime crash that says the memory in the area of "games" is corrupt.
Mar 4 '15 #4
Is it?... I am using tubo C++ version 3 and yours is visual studio.Each one is responding one type for the same coding. So it must be depending on the software used to run the program I guess.anyways thanks a lot.
Mar 5 '15 #5
weaknessforcats
9,208 Expert Mod 8TB
Each compiler is its own implementation of C. So it's not unexpected that different compilers generate different code.
Mar 5 '15 #6

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