total of students by using two array ??

[xtoma]

my program should display each day of the week the number of students attended to the class and show me the total which day 30 students were present in the class specific the day by using searching
i don't know if my program is true or not
can you give me some hints ..


.....


#include<iostream>
using namespace std;
int main()
{
int c=0,pos=-1,i,n=5,x;
int day[15];
bool found=false;

cout<<"please enter attendsin of student in array ";
for(i=0;i<n;i++)
cin>>day[i];

cout<<"please searching of day on which 30 students werw present in the class :";
cin>>x;



while(c<n&&!found)
{
if(day[c]==30)
{
pos=c;
found=true;
}
else
c++;
}
if(found)
cout<<x<<" is found in location "<<pos<<endl;
else
cout<<x<<" is not found "<<endl;

[Brilstern]

xtoma,

Please use code tags to properly format your code. It makes it easier to understand and read for those that would like to help. Example:

[ CODE ]
Remove the spaces around the tag to make this look better.
Function
{
if(x>1)
{
Do x
}

}

[ /CODE ]

 
This looks better.
Function
  {
    if(x>1)
      {
         Do x
      }
 
  }
 
 

[weaknessforcats]

What part is not working?

[xtoma]

well, i want to execute program by using binary search. two correlation array ,so that it appears to me that number of days and number of attendees each day and exact day on which was attended by 30 students ,so it may be monday or sunday .


array[attendees]
array[days]

like this

[weaknessforcats]

Before I offer a solution, do you know hoe to se a struct and a pointer?

[xtoma]

#include<iostream>
using namespace std;
int main()
{
int c=0,pos=-1,i,n,x;
int day[i];
int attended[i];
cout<"please,enter the number of element in array";
cin>>n;
cout<<"please,enter week days";
for(i=0;i<=n;i++)
cin>>day[i];
cout<<"The number of students in every day in the week";
for(i=0;i<=n;i++)
cin>>attended[i];
cout<<"enter searching item";
cin>>x;

bool found =false;
while(c <n&&!found)
{
if(day[c]==x)
{
pos=c;
found=true;
}
else
c++;
}

if (found)
cout<<x<<"is found in location"<<endl;
else
cout<<x<<"is not found"<<endl;
system("pause");
}

[weaknessforcats]

This code:

int day[i];
 

is invalid because the compiler does not know the number of elements for the array. The number of elements must be known at compile time. The value of the variable i won't be known until run time. You have to code something like:

int array[5];

If you really need to create the array at run time with i elements, then you use the malloc() function:

int* array = malloc(i * sizeof(int)); 

You might read: http://bytes.com/topic/c/insights/77...rrays-revealed