accessing pointer inside a nested structure

[vidhya431]

i had a structure as follows:

struct a{
 int x;
 struct b{
  int y;
  b *next;
 }b;
};

when i try to access as follows:

struct a *a;
a->b=a->b->next;

i got the following error:
base operand of ‘->’ has non-pointer type
anyone please help me out.. TIA...

[weaknessforcats]

First, this won't work:

struct a *a;

You cannot have a struct and a variable with the same name. I changed this to:

struct a *var;

Now this won't work:

var->b=var->b->next;

for several reasons. var->b is meaningless since b is a struct. you need to say which member of b gets the assignment.

Also b->next won't work because b is not a pointer. That needs to be changed to b.next

If I choose the next member of b I get:

var->b.next=var->b.next;

which assigns a variable to itself. But it does compile.

What are you trying to do?