Having trouble with printing and performing doubles (very basic)

[MNikz]

So this:

#include <iostream>
#include <cmath>
#include <cstdlib>

using namespace std;

int main()
{
double d = (1/6);
cout<<d;
return 0;
}

returns d as int, the fractional part is removed, can someone tell me why?

[stdq]

Hi! When you calculate 1/6, you are performing integer division, because both 1 and 6 are integers (even though you assign the result to a double variable, is this case, d). To fix this, you could change 1 to 1.0, or 6 to 6.0, or both. Or, you could even perform a cast (a temporary conversion) in at least one of the operands. Cast to double to have more precision. Doing cast, you could do one of the following:

1 / ( (double) 6 )

( (double) 1 ) / 6

( (double) 1 ) / ( (double) 6 )

So, you have 6 options to fix this issue. Bye!

[weaknessforcats]

The preferred style is:

1.0/6.0

These are doubles by definition. Using casts is very common in C but in C++ using them indicates a weakness in the code. You should never have to tell a C++ compiler what the type is.