Problem with WHILE loop?

[sauravamatyaw]

When I execute the program, first it says "enter a number"
then i give a number and it shows output square of this is this...the program is okay till this point.

Then it says "Want to enter another number" and when i type y...the program exits...WHY ITS NOT LOOPING..

#include <stdio.h>
#include <conio.h>
void main()
{
char another = 'y' ;
int num ;
clrscr();
while ( another == 'y' )
{
printf ( "Enter a number " ) ;
scanf ( "%d", &num ) ;
printf ( "square of %d is %d", num, num * num ) ;
printf ( "\nWant to enter another number y/n " ) ;
scanf ( " %c", &another ) ;
}
getch();
}
 

[Shirish]

i think the problem is with your scanf where you accept the user's response.. look carefully.. there is a space in your statement " %c"
it should be

scanf ( "%c", &another );

[gullybaba]

You should write again this program.

[sauravamatyaw]

@Shirish no thats not the problem,...it still doesnt work

[Shirish]

ya.. that's not a problem..

i tried your program on gcc compiler, works fine..

which compiler are you using?

[sauravamatyaw]

@Shirish its Turbo c++

[donbock]

I would flush stdin before the scanf just to make sure there aren't any spurious characters waiting there.

The program will only loop back and repeat for lowercase 'y'. Are you sure you aren't typing uppercase 'Y'?

[Shirish]

@donbock

the program reads an integer and then a character so i don't think there is any need to flush stdin.. the program works fine on gcc..

@sauravamatyaw

as mr. donbock said, you must be entering 'Y' instead of 'y'
or
you must be kidding. good luck