conversion of time in seconds using structure

[haniya ali]

i create a structure called time. Its three members, all type int called hours, minutes, and seconds. This is in 12:59:59 format and i finally want to print out the total number of seconds represented by this time value.
long totalsecs = t1.hours*3600 + t1.minutes*60 + t1.seconds
i am using this formula but facing errors can any one solve it??

[Nepomuk]

Hi haniya ali and welcome to bytes.com!

At first glance the formular looks ok, so you'll have to be a little more specific: What errors are you facing? What goes wrong and what are you expecting?

[haniya ali]

struct TIME
    { 
    int seconds; 
    int minutes;
    int hours; 
     };
    void totalsecs(struct TIME t1,struct TIME*totalsecs ); 
using namespace std;
 
int main()
{     
    struct TIME t1,totalsecs,hours,minutes,; 
    cout<<"Enter the time: \n";
    cout<<"Enter hours, minutes and seconds respectively: "; 
    cin>>t1.hours>>t1.minutes>>t1.seconds;
    cout<<t1.hours<<":"<<t1.minutes<<":"<<t1.seconds;

here is the whole code it works properly but when i apply the formula to calclute seconds then give error

[Nepomuk]

You're declaring totalsecs as a struct TIME in line 12 and in your formular as a long. Such double declarations are not allowed in C/C++; here's a version that works:

#include<iostream>
 
struct TIME
    { 
    int seconds; 
    int minutes;
    int hours; 
     };
    void totalsecs(struct TIME t1,struct TIME*totalsecs ); 
using namespace std;
 
int main()
{     
    struct TIME t1; // totalsecs and others probably aren't of type "TIME", are they?
    cout<<"Enter the time: \n";
    cout<<"Enter hours, minutes and seconds respectively: "; 
    cin>>t1.hours>>t1.minutes>>t1.seconds;
    cout<<t1.hours<<":"<<t1.minutes<<":"<<t1.seconds<<endl;
    long totalsecs = t1.hours*3600 + t1.minutes*60 + t1.seconds;
    cout<<"That makes "<<totalsecs<<" seconds"<<endl;
 
    return 0;
}
 

[haniya ali]

thank you i really works now.