what data type is the result of a caculation on an int and a double?

[annaaaa]

okay for instance

int x = 4;
double y = 2;
 
printf("%d", (x / y + 5));

what data type is
(x / y + 5)
??
thanks

[Banfa]

double

In implicit conversions of this type the compiler always converts up to the type that is largest (holds the largest range of values) in order to get the best chance of using a type that can actually hold the answer.

[weaknessforcats]

The int is converted to double and the result is double.

[donbock]

Consider line 4: you associate conversion specifier "%d" with expression (x / y + 5). printf does not warn you if a conversion specifier does not match the type of the corresponding argument. You might prefer to introduce an intermediate variable so that it will be easier for you to notice a mistaken conversion specifier. The implicit conversions are well-defined, but you may not find it easy to remember them.

int x = 4;
double y = 2;
double z;
 
z = x / y + 5;
printf("%d", z);   // wrong
printf("%f", z);   // right