Converting currency to words just like for checks

[tibialmunik]

how would I go about separating the decimal amount from that of the dollar.

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
 
 
 
int main(int argc, char *argv[]){
 
    char *one[] = {" zero "," one"," two"," three"," four"," five"," six"," seven","eight"," nine"," ten"," eleven"," twelve"," thirteen"," fourteen","fifteen"," sixteen"," seventeen"," eighteen"," nineteen"};
    char *tens[] = {"",""," twenty", " thirty"," forty", " fifty", " sixty", " seventy", " eighty", " ninety", " hundred"};
 
    char input[10];
    //argument
    strcpy(input, argv[1]);
    int dollar;
    int temp;
    float decimal ;
 
 
 
    dollar = atoi(input);
    printf("The dollar value is %i\n", dollar);
 
    decimal = atoi(input) - dollar;
    printf("The decimal value is %3.2f\n", decimal);
 
    decimal = (double) decimal - dollar;
 
    if(dollar == 0){
        printf("%s", one[0]);
    }else{
        if(dollar >= 100){
                temp = dollar / 100;
                dollar = dollar % 100;
                printf("The dollar value is %i \n", dollar);
                printf(" %s%s", one[temp], tens[10]);
            }
 
            if (dollar >= 20){
                temp = dollar /10;
                dollar = dollar%10;
 
                printf("%s ", tens[temp]);
 
            }if(dollar >= 0){
                temp = dollar;
                printf("%s ", one[temp]);
 
 
 
            }
 
 
    }
 
 
 
 
 
 
 
}
 

[weaknessforcats]

If you have an amount, like 251, you get the dollars by 251/100, which is 2.

Next, to get the pennies, reduce the amount by the whole dollars from above. 251 - 2 * 100. which is 51.

Then display a dollar sign + dollar variable + decimal point + pennies:

$2.51

Only you know the decimal point was only displayed and really not part of the vslue anywhere.

Try to never use floating point for money problems. Floating point variables do rounding which can totally screw up a money problem.

Floating point is for scientific stuff where accuracy eed only be approximate.

[Banfa]

In fairness in this situation the user is likely to enter the amount of money as floating point value e.g. "4.35" FOR $4.35 because that is how users think.

However weaknessforcats point about not using floating types holds true so how do you handle this string?

The answer is fairly simple treat it as 2 integers separated by a '.'.

The pseudo code looks something like

input = <valueFromUser>
dollars = atoi(input)
dotindex = findIndexOfDot(input)
centsindex = dotindex + 1
cents = atoi(&input[centsindex])
 
cents += dollars * 100 // optional if you want the full sum cents
 

an alternative that uses a little string processing

input = <valueFromUser>
digitsonly = input with '.' removed
cents = atoi(digitsonly)
 

or finally it wouldn't be too hard to write your own version of atoi that just ignores the '.'

In all cases you need to make sure the user has only entered 2 digits worth of cents.

[tibialmunik]

This is what I ended up doing. Thanks for the help tho.

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
 
 
 
int main(int argc, char *argv[]){
 
    char *one[] = {" zero "," one"," two"," three"," four"," five"," six"," seven","eight"," nine"," ten"," eleven"," twelve"," thirteen"," fourteen","fifteen"," sixteen"," seventeen"," eighteen"," nineteen"};
    char *tens[] = {"",""," twenty", " thirty"," forty", " fifty", " sixty", " seventy", " eighty", " ninety", " hundred"};
 
    char input[10];
    //argument
    strcpy(input, argv[1]);
    float num = atof(input);
    int dollar ;
    int temp;
    double decimal;
 
    //Currency Ammount
    printf("Money: %.2f\n", num);
 
 
 
 
 
    //Separates whole number from decimal
    dollar = (int)num;
    printf("The dollar value is %d\n", dollar);
 
    //Separates decimal from whole number and prints as float
    decimal = num -dollar;
    printf("The decimal value is %.2f\n", decimal);
 
 
 
 
    //prints out zero if amount is 0
    if(dollar == 0){
        printf("%s", one[0]);
    }else{
        //prints out hundred amount
        if(dollar >= 100){
                temp = dollar / 100;
                dollar = dollar % 100;
                printf("The dollar value is %i \n", dollar);
                printf(" %s%s", one[temp], tens[10]);
            }
             //prints out tens place amount
            if (dollar >= 20){
                temp = dollar /10;
                dollar = dollar%10;
 
                printf("%s ", tens[temp]);
             //prints out one place amount
            }if(dollar >= 0){
                temp = dollar;
                printf("%s ", one[temp]);
            //converst decimal to whole number and prints out as cent fraction
            }if(decimal >0){
                decimal = (double)decimal *100;
 
                printf("and %.0f \\100 \n", decimal);
            }
 
 
    }
 
 
 
 
 
 
 
}