Help me fix this code: Finding the missing number in the array

polkodot

I'm trying to write a program where in you input 9 numbers from 1-10, then it determines the missing number. Here's my code. It has a lot of errors. Help me do the right structure. Maybe after that, I'll improve it by setting conditions like no repetition/ 0< number <10. Just help me to fix this first:


I'm so new to C++. It always prints out the number 10 even though I typed it already. I really have no idea how to determine the missing one.

Nov 27 '12 #1

whodgson

There are 10 numbers between 1 and 10 inclusive and there are 10
integers in d[]. Your two loop conditions are 8 and 9. Other than those observations I have no idea what you are doing.
*"It always prints out the number 10"
this is because when j<10 or 9 (and finishes iterating)it has reached the last array element which contains 10. Remember j starts counting at 0.

Nov 27 '12 #2

wholetthedogout

Can't this be an easiest approach

1) Sort the given sequence
2) fix the no. with the difference of two consecutive no. as > 1; duplicates can be filtered out with the difference as zero.

Hope this help.

Nov 27 '12 #3

whodgson

Or you could:
1)Inside a loop iterate through the array and at each element compare loop i with array[i].If they are equal (==) continue.

Nov 28 '12 #4