How to pass the arguments as a two-dimensional array of typedef to function

[kim12]

Please help me out. I graduated 10 years ago in Computer Information Systems. But my job doesn't related to what I studied. Luckly, My best friend help me find a job in this field to improve my technical skill.
I am training right now. I am wondering if you or somebody can explain to me about the typedef 2-dimensional arry.
Suppose I have typedef two_Darr[3][3];
Can you tell me how to declare this and how to pass it to other function definition in the main function

I appreciated that all your help.

thank you again.

[weaknessforcats]

Read this: http://bytes.com/topic/c/insights/77...rrays-revealed.

Your question is answered in this article. Post again if you need more info.

[donbock]

Presumably you meant something more like this:

typedef int two_Darr[3][3];

[weaknessforcats]

First, an array can't be a type. It is a collection of many things of the same type.

Second, the name of the array is the address of element 0.

Third, element 0 has a type.

Therefore, you can typedef that address. This array:

int two_Darr[3][3];

is an array of 3 elements where wach element is an array of 3 int. Therefore, element 0 is the address of an array of three int.

typedef int (*MyArray)[3];

would say that MyArray is a pointer to an array of 3 int.

So this should work:

int arr[3][3];
MyArray ptr;
ptr = arr;