Is it possible to initialize values to a single variable using '( )'

[Jomon]

int a;
a=(32,3,3,4,77,48);

what is the meaning of above initialization?
can you please help me?

[weaknessforcats]

The variable is initialized using a list involving the comma operator.
=(32,3,3,4,77,48);

So the variable is initialized to 32, then changed to 3, then changed to 3 again, then changed to 4, then changed to 77 and finally changed to 48.

This has to be from some class or textbook.

[axiagame]

I would rather say that the comma operator evaluate each operation one after each other. As you use parenthesis, everything inside is evaluated, then the assignment is done with the last evaluation done inside the parenthesis, i.e 48.

Then only 48 should be assigned to the "a" variable. 32 is evaluated, but since it is only a value nothing is done. The same for 3, 3, 4, 77 and finally 48. 48 being the last operation, it is the value that "gets out the parenthesis". Then a = 48 is evaluated, and 48 is stored into a.

But whatever the way it works, a will have the same value, and if you have a good compiler all of this will be optimized to a = 48.

[donbock]

To be clear, in my personal opinion you should never write code that looks like this. It looks like a contrived example to demonstrate the more obscure implications of the comma operator.

The only exception I can think of is an entry in The Obfuscated C Contest.