pointer to char array

[nishantporwal]

Program : -

#include<iostream.h>
char *fl[5]={0};
void print1();

void main()
{
char p[3]="";
int lng=52;
for (int j=0; j<=strlen("think") ;j++ , lng++ )
{
sprintf(p,"%d",lng);
fl[j]=p;
cout<<"Value in loop is--> " << fl[j]<<endl;
}
print1();
}

void print1()
{
for(int i=0; i<=5; i++)
cout <<"Value after--> "<<fl[i]<<endl;
}



Output : -

./123
Value in loop is--> 52
Value in loop is--> 53
Value in loop is--> 54
Value in loop is--> 55
Value in loop is--> 56
Value in loop is--> 57
Value after--> 57
Value after--> 57
Value after--> 57
Value after--> 57
Value after--> 57
Value after--> 57


Issue : - Statement fl[j]=p; is setting all the elements of the array as the same value , pl help !!

[weaknessforcats]

You only have one array p.

You assign p to every element of f.

Therefore, the last value you put in p will appear as the value for
every element of f.

You need to allocate a new p array for every element of f. Then you will be able to aev searate values for every f element.